Metamath Proof Explorer


Theorem omndaddr

Description: In a right ordered monoid, the ordering is compatible with group addition. (Contributed by Thierry Arnoux, 30-Jan-2018)

Ref Expression
Hypotheses omndadd.0 ⊢ B = Base M
omndadd.1 ⊢ ≤ ˙ = ≤ M
omndadd.2 ⊢ + ˙ = + M
Assertion omndaddr ⊢ opp 𝑔 ⁡ M ∈ oMnd ∧ X ∈ B ∧ Y ∈ B ∧ Z ∈ B ∧ X ≤ ˙ Y → Z + ˙ X ≤ ˙ Z + ˙ Y

Proof

Step Hyp Ref Expression
1 omndadd.0 ⊢ B = Base M
2 omndadd.1 ⊢ ≤ ˙ = ≤ M
3 omndadd.2 ⊢ + ˙ = + M
4 eqid ⊢ opp 𝑔 ⁡ M = opp 𝑔 ⁡ M
5 4 1 oppgbas ⊢ B = Base opp 𝑔 ⁡ M
6 4 2 oppgle ⊢ ≤ ˙ = ≤ opp 𝑔 ⁡ M
7 eqid ⊢ + opp 𝑔 ⁡ M = + opp 𝑔 ⁡ M
8 5 6 7 omndadd ⊢ opp 𝑔 ⁡ M ∈ oMnd ∧ X ∈ B ∧ Y ∈ B ∧ Z ∈ B ∧ X ≤ ˙ Y → X + opp 𝑔 ⁡ M Z ≤ ˙ Y + opp 𝑔 ⁡ M Z
9 3 4 7 oppgplus ⊢ X + opp 𝑔 ⁡ M Z = Z + ˙ X
10 3 4 7 oppgplus ⊢ Y + opp 𝑔 ⁡ M Z = Z + ˙ Y
11 8 9 10 3brtr3g ⊢ opp 𝑔 ⁡ M ∈ oMnd ∧ X ∈ B ∧ Y ∈ B ∧ Z ∈ B ∧ X ≤ ˙ Y → Z + ˙ X ≤ ˙ Z + ˙ Y