Metamath Proof Explorer


Theorem otthg

Description: Ordered triple theorem, closed form. (Contributed by Alexander van der Vekens, 10-Mar-2018)

Ref Expression
Assertion otthg ⊢ A ∈ U ∧ B ∈ V ∧ C ∈ W → A B C = D E F ↔ A = D ∧ B = E ∧ C = F

Proof

Step Hyp Ref Expression
1 df-ot ⊢ A B C = A B C
2 df-ot ⊢ D E F = D E F
3 1 2 eqeq12i ⊢ A B C = D E F ↔ A B C = D E F
4 opex ⊢ A B ∈ V
5 opthg ⊢ A B ∈ V ∧ C ∈ W → A B C = D E F ↔ A B = D E ∧ C = F
6 4 5 mpan ⊢ C ∈ W → A B C = D E F ↔ A B = D E ∧ C = F
7 opthg ⊢ A ∈ U ∧ B ∈ V → A B = D E ↔ A = D ∧ B = E
8 7 anbi1d ⊢ A ∈ U ∧ B ∈ V → A B = D E ∧ C = F ↔ A = D ∧ B = E ∧ C = F
9 df-3an ⊢ A = D ∧ B = E ∧ C = F ↔ A = D ∧ B = E ∧ C = F
10 8 9 bitr4di ⊢ A ∈ U ∧ B ∈ V → A B = D E ∧ C = F ↔ A = D ∧ B = E ∧ C = F
11 6 10 sylan9bbr ⊢ A ∈ U ∧ B ∈ V ∧ C ∈ W → A B C = D E F ↔ A = D ∧ B = E ∧ C = F
12 11 3impa ⊢ A ∈ U ∧ B ∈ V ∧ C ∈ W → A B C = D E F ↔ A = D ∧ B = E ∧ C = F
13 3 12 bitrid ⊢ A ∈ U ∧ B ∈ V ∧ C ∈ W → A B C = D E F ↔ A = D ∧ B = E ∧ C = F