Metamath Proof Explorer


Theorem ovolssnul

Description: A subset of a nullset is null. (Contributed by Mario Carneiro, 19-Mar-2014)

Ref Expression
Assertion ovolssnul ⊢ A ⊆ B ∧ B ⊆ ℝ ∧ vol * ⁡ B = 0 → vol * ⁡ A = 0

Proof

Step Hyp Ref Expression
1 ovolss ⊢ A ⊆ B ∧ B ⊆ ℝ → vol * ⁡ A ≤ vol * ⁡ B
2 1 3adant3 ⊢ A ⊆ B ∧ B ⊆ ℝ ∧ vol * ⁡ B = 0 → vol * ⁡ A ≤ vol * ⁡ B
3 simp3 ⊢ A ⊆ B ∧ B ⊆ ℝ ∧ vol * ⁡ B = 0 → vol * ⁡ B = 0
4 2 3 breqtrd ⊢ A ⊆ B ∧ B ⊆ ℝ ∧ vol * ⁡ B = 0 → vol * ⁡ A ≤ 0
5 sstr ⊢ A ⊆ B ∧ B ⊆ ℝ → A ⊆ ℝ
6 5 3adant3 ⊢ A ⊆ B ∧ B ⊆ ℝ ∧ vol * ⁡ B = 0 → A ⊆ ℝ
7 ovolge0 ⊢ A ⊆ ℝ → 0 ≤ vol * ⁡ A
8 6 7 syl ⊢ A ⊆ B ∧ B ⊆ ℝ ∧ vol * ⁡ B = 0 → 0 ≤ vol * ⁡ A
9 ovolcl ⊢ A ⊆ ℝ → vol * ⁡ A ∈ ℝ *
10 6 9 syl ⊢ A ⊆ B ∧ B ⊆ ℝ ∧ vol * ⁡ B = 0 → vol * ⁡ A ∈ ℝ *
11 0xr ⊢ 0 ∈ ℝ *
12 xrletri3 ⊢ vol * ⁡ A ∈ ℝ * ∧ 0 ∈ ℝ * → vol * ⁡ A = 0 ↔ vol * ⁡ A ≤ 0 ∧ 0 ≤ vol * ⁡ A
13 10 11 12 sylancl ⊢ A ⊆ B ∧ B ⊆ ℝ ∧ vol * ⁡ B = 0 → vol * ⁡ A = 0 ↔ vol * ⁡ A ≤ 0 ∧ 0 ≤ vol * ⁡ A
14 4 8 13 mpbir2and ⊢ A ⊆ B ∧ B ⊆ ℝ ∧ vol * ⁡ B = 0 → vol * ⁡ A = 0