Metamath Proof Explorer


Theorem prdsplusgval

Description: Value of a componentwise sum in a structure product. (Contributed by Stefan O'Rear, 10-Jan-2015) (Revised by Mario Carneiro, 15-Aug-2015)

Ref Expression
Hypotheses prdsbasmpt.y ⊢ Y = S ⨉ 𝑠 R
prdsbasmpt.b ⊢ B = Base Y
prdsbasmpt.s ⊢ φ → S ∈ V
prdsbasmpt.i ⊢ φ → I ∈ W
prdsbasmpt.r ⊢ φ → R Fn I
prdsplusgval.f ⊢ φ → F ∈ B
prdsplusgval.g ⊢ φ → G ∈ B
prdsplusgval.p ⊢ + ˙ = + Y
Assertion prdsplusgval ⊢ φ → F + ˙ G = x ∈ I ⟼ F ⁡ x + R ⁡ x G ⁡ x

Proof

Step Hyp Ref Expression
1 prdsbasmpt.y ⊢ Y = S ⨉ 𝑠 R
2 prdsbasmpt.b ⊢ B = Base Y
3 prdsbasmpt.s ⊢ φ → S ∈ V
4 prdsbasmpt.i ⊢ φ → I ∈ W
5 prdsbasmpt.r ⊢ φ → R Fn I
6 prdsplusgval.f ⊢ φ → F ∈ B
7 prdsplusgval.g ⊢ φ → G ∈ B
8 prdsplusgval.p ⊢ + ˙ = + Y
9 fnex ⊢ R Fn I ∧ I ∈ W → R ∈ V
10 5 4 9 syl2anc ⊢ φ → R ∈ V
11 5 fndmd ⊢ φ → dom ⁡ R = I
12 1 3 10 2 11 8 prdsplusg ⊢ φ → + ˙ = y ∈ B , z ∈ B ⟼ x ∈ I ⟼ y ⁡ x + R ⁡ x z ⁡ x
13 fveq1 ⊢ y = F → y ⁡ x = F ⁡ x
14 fveq1 ⊢ z = G → z ⁡ x = G ⁡ x
15 13 14 oveqan12d ⊢ y = F ∧ z = G → y ⁡ x + R ⁡ x z ⁡ x = F ⁡ x + R ⁡ x G ⁡ x
16 15 adantl ⊢ φ ∧ y = F ∧ z = G → y ⁡ x + R ⁡ x z ⁡ x = F ⁡ x + R ⁡ x G ⁡ x
17 16 mpteq2dv ⊢ φ ∧ y = F ∧ z = G → x ∈ I ⟼ y ⁡ x + R ⁡ x z ⁡ x = x ∈ I ⟼ F ⁡ x + R ⁡ x G ⁡ x
18 4 mptexd ⊢ φ → x ∈ I ⟼ F ⁡ x + R ⁡ x G ⁡ x ∈ V
19 12 17 6 7 18 ovmpod ⊢ φ → F + ˙ G = x ∈ I ⟼ F ⁡ x + R ⁡ x G ⁡ x