Metamath Proof Explorer


Theorem prdsvscafval

Description: Scalar multiplication of a single coordinate in a structure product. (Contributed by Stefan O'Rear, 10-Jan-2015)

Ref Expression
Hypotheses prdsbasmpt.y ⊢ Y = S ⨉ 𝑠 R
prdsbasmpt.b ⊢ B = Base Y
prdsvscaval.t ⊢ · ˙ = ⋅ Y
prdsvscaval.k ⊢ K = Base S
prdsvscaval.s ⊢ φ → S ∈ V
prdsvscaval.i ⊢ φ → I ∈ W
prdsvscaval.r ⊢ φ → R Fn I
prdsvscaval.f ⊢ φ → F ∈ K
prdsvscaval.g ⊢ φ → G ∈ B
prdsvscafval.j ⊢ φ → J ∈ I
Assertion prdsvscafval ⊢ φ → F · ˙ G ⁡ J = F ⋅ R ⁡ J G ⁡ J

Proof

Step Hyp Ref Expression
1 prdsbasmpt.y ⊢ Y = S ⨉ 𝑠 R
2 prdsbasmpt.b ⊢ B = Base Y
3 prdsvscaval.t ⊢ · ˙ = ⋅ Y
4 prdsvscaval.k ⊢ K = Base S
5 prdsvscaval.s ⊢ φ → S ∈ V
6 prdsvscaval.i ⊢ φ → I ∈ W
7 prdsvscaval.r ⊢ φ → R Fn I
8 prdsvscaval.f ⊢ φ → F ∈ K
9 prdsvscaval.g ⊢ φ → G ∈ B
10 prdsvscafval.j ⊢ φ → J ∈ I
11 1 2 3 4 5 6 7 8 9 prdsvscaval ⊢ φ → F · ˙ G = x ∈ I ⟼ F ⋅ R ⁡ x G ⁡ x
12 2fveq3 ⊢ x = J → ⋅ R ⁡ x = ⋅ R ⁡ J
13 eqidd ⊢ x = J → F = F
14 fveq2 ⊢ x = J → G ⁡ x = G ⁡ J
15 12 13 14 oveq123d ⊢ x = J → F ⋅ R ⁡ x G ⁡ x = F ⋅ R ⁡ J G ⁡ J
16 15 adantl ⊢ φ ∧ x = J → F ⋅ R ⁡ x G ⁡ x = F ⋅ R ⁡ J G ⁡ J
17 ovexd ⊢ φ → F ⋅ R ⁡ J G ⁡ J ∈ V
18 11 16 10 17 fvmptd ⊢ φ → F · ˙ G ⁡ J = F ⋅ R ⁡ J G ⁡ J