Metamath Proof Explorer


Theorem prjspnequivnorm

Description: In a free module, a nonzero vector is equivalent to its normalized vector. (Contributed by SN, 24-Sep-2026)

Ref Expression
Hypotheses prjspnnorm.e ⊢ ∼ ˙ = x y | x ∈ B ∧ y ∈ B ∧ ∃ l ∈ S x = l · ˙ y
prjspnnorm.j ⊢ J = b ∈ B ⟼ inf i ∈ 0 … N | b ⁡ i ≠ 0 K ℝ <
prjspnnorm.f ⊢ F = v ∈ B ⟼ I ⁡ v ⁡ J ⁡ v · ˙ v
prjspnnorm.w ⊢ W = K freeLMod 0 … N
prjspnnorm.b ⊢ B = Base W ∖ 0 W
prjspnnorm.s ⊢ S = Base K
prjspnnorm.i ⊢ I = inv r ⁡ K
prjspnnorm.t ⊢ · ˙ = ⋅ W
prjspnnorm.k ⊢ φ → K ∈ DivRing
prjspnnorm.n ⊢ φ → N ∈ ℕ 0
prjspnnorm.x ⊢ φ → X ∈ B
Assertion prjspnequivnorm ⊢ φ → X ∼ ˙ F ⁡ X

Proof

Step Hyp Ref Expression
1 prjspnnorm.e ⊢ ∼ ˙ = x y | x ∈ B ∧ y ∈ B ∧ ∃ l ∈ S x = l · ˙ y
2 prjspnnorm.j ⊢ J = b ∈ B ⟼ inf i ∈ 0 … N | b ⁡ i ≠ 0 K ℝ <
3 prjspnnorm.f ⊢ F = v ∈ B ⟼ I ⁡ v ⁡ J ⁡ v · ˙ v
4 prjspnnorm.w ⊢ W = K freeLMod 0 … N
5 prjspnnorm.b ⊢ B = Base W ∖ 0 W
6 prjspnnorm.s ⊢ S = Base K
7 prjspnnorm.i ⊢ I = inv r ⁡ K
8 prjspnnorm.t ⊢ · ˙ = ⋅ W
9 prjspnnorm.k ⊢ φ → K ∈ DivRing
10 prjspnnorm.n ⊢ φ → N ∈ ℕ 0
11 prjspnnorm.x ⊢ φ → X ∈ B
12 1 4 5 6 8 9 prjspner ⊢ φ → ∼ ˙ Er B
13 eqid ⊢ 0 K = 0 K
14 9 drngringd ⊢ φ → K ∈ Ring
15 2 4 5 14 10 11 6 frlmnzcoordcl2 ⊢ φ → X ⁡ J ⁡ X ∈ S
16 2 4 5 14 10 11 frlmnzcoordn0 ⊢ φ → X ⁡ J ⁡ X ≠ 0 K
17 6 13 7 9 15 16 drnginvrcld ⊢ φ → I ⁡ X ⁡ J ⁡ X ∈ S
18 6 13 7 9 15 16 drnginvrn0d ⊢ φ → I ⁡ X ⁡ J ⁡ X ≠ 0 K
19 1 4 5 6 8 13 9 11 17 18 prjspnvs ⊢ φ → I ⁡ X ⁡ J ⁡ X · ˙ X ∼ ˙ X
20 12 19 ersym ⊢ φ → X ∼ ˙ I ⁡ X ⁡ J ⁡ X · ˙ X
21 3 11 prjspnnormval ⊢ φ → F ⁡ X = I ⁡ X ⁡ J ⁡ X · ˙ X
22 20 21 breqtrrd ⊢ φ → X ∼ ˙ F ⁡ X