Metamath Proof Explorer


Theorem prlngsymquad

Description: All parallelograms are symmetric quadrilaterals. First part of Theorem 12.19 of Schwabhauser p. 126. (Contributed by Thierry Arnoux, 20-Jul-2026)

Ref Expression
Hypotheses symquadprlng.p ⊢ P = Base G
symquadprlng.d ⊢ - ˙ = dist ⁡ G
symquadprlng.l ⊢ L = Line 𝒢 ⁡ G
symquadprlng.r No typesetting found for |- .|| = ( parlnG ` G ) with typecode |-
symquadprlng.g ⊢ φ → G ∈ 𝒢 Tarski
symquadprlng.1 ⊢ φ → G ∈ 𝒢 Tarski E
symquadprlng.x ⊢ φ → X ∈ P
symquadprlng.y ⊢ φ → Y ∈ P
symquadprlng.z ⊢ φ → Z ∈ P
symquadprlng.w ⊢ φ → W ∈ P
prlngsymquad.2 ⊢ φ → ¬ X ∈ Y L Z ∨ Y = Z
prlngsymquad.3 ⊢ φ → X L Y ∥ ˙ Z L W
prlngsymquad.4 ⊢ φ → Y L Z ∥ ˙ W L X
Assertion prlngsymquad ⊢ φ → X - ˙ Y = Z - ˙ W ∧ Y - ˙ Z = W - ˙ X

Proof

Step Hyp Ref Expression
1 symquadprlng.p ⊢ P = Base G
2 symquadprlng.d ⊢ - ˙ = dist ⁡ G
3 symquadprlng.l ⊢ L = Line 𝒢 ⁡ G
4 symquadprlng.r Could not format .|| = ( parlnG ` G ) : No typesetting found for |- .|| = ( parlnG ` G ) with typecode |-
5 symquadprlng.g ⊢ φ → G ∈ 𝒢 Tarski
6 symquadprlng.1 ⊢ φ → G ∈ 𝒢 Tarski E
7 symquadprlng.x ⊢ φ → X ∈ P
8 symquadprlng.y ⊢ φ → Y ∈ P
9 symquadprlng.z ⊢ φ → Z ∈ P
10 symquadprlng.w ⊢ φ → W ∈ P
11 prlngsymquad.2 ⊢ φ → ¬ X ∈ Y L Z ∨ Y = Z
12 prlngsymquad.3 ⊢ φ → X L Y ∥ ˙ Z L W
13 prlngsymquad.4 ⊢ φ → Y L Z ∥ ˙ W L X
14 eqidd ⊢ φ → X mid 𝒢 ⁡ G Z = X mid 𝒢 ⁡ G Z
15 eqid ⊢ Itv ⁡ G = Itv ⁡ G
16 1 3 15 5 8 9 7 11 ncoltgdim2 ⊢ φ → G Dim 𝒢 ≥ 2
17 eqid ⊢ pInv 𝒢 ⁡ G = pInv 𝒢 ⁡ G
18 1 2 15 5 16 7 9 midcl ⊢ φ → X mid 𝒢 ⁡ G Z ∈ P
19 1 2 15 5 16 7 9 17 18 ismidb ⊢ φ → Z = pInv 𝒢 ⁡ G ⁡ X mid 𝒢 ⁡ G Z ⁡ X ↔ X mid 𝒢 ⁡ G Z = X mid 𝒢 ⁡ G Z
20 14 19 mpbird ⊢ φ → Z = pInv 𝒢 ⁡ G ⁡ X mid 𝒢 ⁡ G Z ⁡ X
21 20 eqcomd ⊢ φ → pInv 𝒢 ⁡ G ⁡ X mid 𝒢 ⁡ G Z ⁡ X = Z
22 21 oveq1d ⊢ φ → pInv 𝒢 ⁡ G ⁡ X mid 𝒢 ⁡ G Z ⁡ X - ˙ pInv 𝒢 ⁡ G ⁡ X mid 𝒢 ⁡ G Z ⁡ Y = Z - ˙ pInv 𝒢 ⁡ G ⁡ X mid 𝒢 ⁡ G Z ⁡ Y
23 eqid ⊢ pInv 𝒢 ⁡ G ⁡ X mid 𝒢 ⁡ G Z = pInv 𝒢 ⁡ G ⁡ X mid 𝒢 ⁡ G Z
24 1 2 15 3 17 5 18 23 7 8 miriso ⊢ φ → pInv 𝒢 ⁡ G ⁡ X mid 𝒢 ⁡ G Z ⁡ X - ˙ pInv 𝒢 ⁡ G ⁡ X mid 𝒢 ⁡ G Z ⁡ Y = X - ˙ Y
25 eqid ⊢ pInv 𝒢 ⁡ G ⁡ X mid 𝒢 ⁡ G Z ⁡ Y = pInv 𝒢 ⁡ G ⁡ X mid 𝒢 ⁡ G Z ⁡ Y
26 1 2 3 4 5 6 7 8 9 10 11 12 13 25 prlngsymquadlem ⊢ φ → pInv 𝒢 ⁡ G ⁡ X mid 𝒢 ⁡ G Z ⁡ Y = W
27 26 oveq2d ⊢ φ → Z - ˙ pInv 𝒢 ⁡ G ⁡ X mid 𝒢 ⁡ G Z ⁡ Y = Z - ˙ W
28 22 24 27 3eqtr3d ⊢ φ → X - ˙ Y = Z - ˙ W
29 1 2 15 3 17 5 18 23 7 21 mircom ⊢ φ → pInv 𝒢 ⁡ G ⁡ X mid 𝒢 ⁡ G Z ⁡ Z = X
30 29 oveq2d ⊢ φ → pInv 𝒢 ⁡ G ⁡ X mid 𝒢 ⁡ G Z ⁡ Y - ˙ pInv 𝒢 ⁡ G ⁡ X mid 𝒢 ⁡ G Z ⁡ Z = pInv 𝒢 ⁡ G ⁡ X mid 𝒢 ⁡ G Z ⁡ Y - ˙ X
31 1 2 15 3 17 5 18 23 8 9 miriso ⊢ φ → pInv 𝒢 ⁡ G ⁡ X mid 𝒢 ⁡ G Z ⁡ Y - ˙ pInv 𝒢 ⁡ G ⁡ X mid 𝒢 ⁡ G Z ⁡ Z = Y - ˙ Z
32 26 oveq1d ⊢ φ → pInv 𝒢 ⁡ G ⁡ X mid 𝒢 ⁡ G Z ⁡ Y - ˙ X = W - ˙ X
33 30 31 32 3eqtr3d ⊢ φ → Y - ˙ Z = W - ˙ X
34 28 33 jca ⊢ φ → X - ˙ Y = Z - ˙ W ∧ Y - ˙ Z = W - ˙ X