Metamath Proof Explorer


Theorem pwdom

Description: Injection of sets implies injection on power sets. (Contributed by Mario Carneiro, 9-Apr-2015)

Ref Expression
Assertion pwdom ⊢ A ≼ B → 𝒫 A ≼ 𝒫 B

Proof

Step Hyp Ref Expression
1 pweq ⊢ A = ∅ → 𝒫 A = 𝒫 ∅
2 1 breq1d ⊢ A = ∅ → 𝒫 A ≼ 𝒫 B ↔ 𝒫 ∅ ≼ 𝒫 B
3 reldom ⊢ Rel ⁡ ≼
4 3 brrelex1i ⊢ A ≼ B → A ∈ V
5 0sdomg ⊢ A ∈ V → ∅ ≺ A ↔ A ≠ ∅
6 4 5 syl ⊢ A ≼ B → ∅ ≺ A ↔ A ≠ ∅
7 6 biimpar ⊢ A ≼ B ∧ A ≠ ∅ → ∅ ≺ A
8 simpl ⊢ A ≼ B ∧ A ≠ ∅ → A ≼ B
9 fodomr ⊢ ∅ ≺ A ∧ A ≼ B → ∃ f f : B ⟶ onto A
10 7 8 9 syl2anc ⊢ A ≼ B ∧ A ≠ ∅ → ∃ f f : B ⟶ onto A
11 vex ⊢ f ∈ V
12 fopwdom ⊢ f ∈ V ∧ f : B ⟶ onto A → 𝒫 A ≼ 𝒫 B
13 11 12 mpan ⊢ f : B ⟶ onto A → 𝒫 A ≼ 𝒫 B
14 13 exlimiv ⊢ ∃ f f : B ⟶ onto A → 𝒫 A ≼ 𝒫 B
15 10 14 syl ⊢ A ≼ B ∧ A ≠ ∅ → 𝒫 A ≼ 𝒫 B
16 3 brrelex2i ⊢ A ≼ B → B ∈ V
17 16 pwexd ⊢ A ≼ B → 𝒫 B ∈ V
18 0ss ⊢ ∅ ⊆ B
19 18 sspwi ⊢ 𝒫 ∅ ⊆ 𝒫 B
20 ssdomg ⊢ 𝒫 B ∈ V → 𝒫 ∅ ⊆ 𝒫 B → 𝒫 ∅ ≼ 𝒫 B
21 17 19 20 mpisyl ⊢ A ≼ B → 𝒫 ∅ ≼ 𝒫 B
22 2 15 21 pm2.61ne ⊢ A ≼ B → 𝒫 A ≼ 𝒫 B