Metamath Proof Explorer


Theorem recms

Description: The real numbers form a complete metric space. (Contributed by Thierry Arnoux, 1-Nov-2017)

Ref Expression
Assertion recms ⊢ ℝ fld ∈ CMetSp

Proof

Step Hyp Ref Expression
1 eqid ⊢ TopOpen ⁡ ℂ fld = TopOpen ⁡ ℂ fld
2 1 recld2 ⊢ ℝ ∈ Clsd ⁡ TopOpen ⁡ ℂ fld
3 cncms ⊢ ℂ fld ∈ CMetSp
4 ax-resscn ⊢ ℝ ⊆ ℂ
5 df-refld ⊢ ℝ fld = ℂ fld ↾ 𝑠 ℝ
6 cnfldbas ⊢ ℂ = Base ℂ fld
7 5 6 1 cmsss ⊢ ℂ fld ∈ CMetSp ∧ ℝ ⊆ ℂ → ℝ fld ∈ CMetSp ↔ ℝ ∈ Clsd ⁡ TopOpen ⁡ ℂ fld
8 3 4 7 mp2an ⊢ ℝ fld ∈ CMetSp ↔ ℝ ∈ Clsd ⁡ TopOpen ⁡ ℂ fld
9 2 8 mpbir ⊢ ℝ fld ∈ CMetSp