Metamath Proof Explorer


Theorem restclssep

Description: Two disjoint closed sets in a subspace topology are separated in the original topology. (Contributed by Zhi Wang, 2-Sep-2024)

Ref Expression
Hypotheses restcls2.1 ⊢ φ → J ∈ Top
restcls2.2 ⊢ φ → X = ⋃ J
restcls2.3 ⊢ φ → Y ⊆ X
restcls2.4 ⊢ φ → K = J ↾ 𝑡 Y
restcls2.5 ⊢ φ → S ∈ Clsd ⁡ K
restclsseplem.6 ⊢ φ → S ∩ T = ∅
restclssep.7 ⊢ φ → T ∈ Clsd ⁡ K
Assertion restclssep ⊢ φ → S ∩ cls ⁡ J ⁡ T = ∅ ∧ cls ⁡ J ⁡ S ∩ T = ∅

Proof

Step Hyp Ref Expression
1 restcls2.1 ⊢ φ → J ∈ Top
2 restcls2.2 ⊢ φ → X = ⋃ J
3 restcls2.3 ⊢ φ → Y ⊆ X
4 restcls2.4 ⊢ φ → K = J ↾ 𝑡 Y
5 restcls2.5 ⊢ φ → S ∈ Clsd ⁡ K
6 restclsseplem.6 ⊢ φ → S ∩ T = ∅
7 restclssep.7 ⊢ φ → T ∈ Clsd ⁡ K
8 incom ⊢ cls ⁡ J ⁡ T ∩ S = S ∩ cls ⁡ J ⁡ T
9 incom ⊢ S ∩ T = T ∩ S
10 9 6 eqtr3id ⊢ φ → T ∩ S = ∅
11 1 2 3 4 5 restcls2lem ⊢ φ → S ⊆ Y
12 1 2 3 4 7 10 11 restclsseplem ⊢ φ → cls ⁡ J ⁡ T ∩ S = ∅
13 8 12 eqtr3id ⊢ φ → S ∩ cls ⁡ J ⁡ T = ∅
14 1 2 3 4 7 restcls2lem ⊢ φ → T ⊆ Y
15 1 2 3 4 5 6 14 restclsseplem ⊢ φ → cls ⁡ J ⁡ S ∩ T = ∅
16 13 15 jca ⊢ φ → S ∩ cls ⁡ J ⁡ T = ∅ ∧ cls ⁡ J ⁡ S ∩ T = ∅