Metamath Proof Explorer


Theorem restclsseplem

Description: Lemma for restclssep . (Contributed by Zhi Wang, 2-Sep-2024)

Ref Expression
Hypotheses restcls2.1 ⊢ φ → J ∈ Top
restcls2.2 ⊢ φ → X = ⋃ J
restcls2.3 ⊢ φ → Y ⊆ X
restcls2.4 ⊢ φ → K = J ↾ 𝑡 Y
restcls2.5 ⊢ φ → S ∈ Clsd ⁡ K
restclsseplem.6 ⊢ φ → S ∩ T = ∅
restclsseplem.7 ⊢ φ → T ⊆ Y
Assertion restclsseplem ⊢ φ → cls ⁡ J ⁡ S ∩ T = ∅

Proof

Step Hyp Ref Expression
1 restcls2.1 ⊢ φ → J ∈ Top
2 restcls2.2 ⊢ φ → X = ⋃ J
3 restcls2.3 ⊢ φ → Y ⊆ X
4 restcls2.4 ⊢ φ → K = J ↾ 𝑡 Y
5 restcls2.5 ⊢ φ → S ∈ Clsd ⁡ K
6 restclsseplem.6 ⊢ φ → S ∩ T = ∅
7 restclsseplem.7 ⊢ φ → T ⊆ Y
8 1 2 3 4 5 restcls2 ⊢ φ → S = cls ⁡ J ⁡ S ∩ Y
9 8 ineq1d ⊢ φ → S ∩ T = cls ⁡ J ⁡ S ∩ Y ∩ T
10 inass ⊢ cls ⁡ J ⁡ S ∩ Y ∩ T = cls ⁡ J ⁡ S ∩ Y ∩ T
11 9 10 eqtrdi ⊢ φ → S ∩ T = cls ⁡ J ⁡ S ∩ Y ∩ T
12 sseqin2 ⊢ T ⊆ Y ↔ Y ∩ T = T
13 7 12 sylib ⊢ φ → Y ∩ T = T
14 13 ineq2d ⊢ φ → cls ⁡ J ⁡ S ∩ Y ∩ T = cls ⁡ J ⁡ S ∩ T
15 11 6 14 3eqtr3rd ⊢ φ → cls ⁡ J ⁡ S ∩ T = ∅