Metamath Proof Explorer


Theorem rexabsobidv

Description: Formula-building lemma for proving absoluteness results. (Contributed by Eric Schmidt, 19-Oct-2025)

Ref Expression
Hypotheses ralabsod.1 ⊢ φ → Tr ⁡ M
ralabsobidv.2 ⊢ φ → ψ ↔ χ
Assertion rexabsobidv ⊢ φ ∧ A ∈ M → ∃ x ∈ A ψ ↔ ∃ x ∈ M x ∈ A ∧ χ

Proof

Step Hyp Ref Expression
1 ralabsod.1 ⊢ φ → Tr ⁡ M
2 ralabsobidv.2 ⊢ φ → ψ ↔ χ
3 2 rexbidv ⊢ φ → ∃ x ∈ A ψ ↔ ∃ x ∈ A χ
4 3 adantr ⊢ φ ∧ A ∈ M → ∃ x ∈ A ψ ↔ ∃ x ∈ A χ
5 1 rexabsod ⊢ φ ∧ A ∈ M → ∃ x ∈ A χ ↔ ∃ x ∈ M x ∈ A ∧ χ
6 4 5 bitrd ⊢ φ ∧ A ∈ M → ∃ x ∈ A ψ ↔ ∃ x ∈ M x ∈ A ∧ χ