Metamath Proof Explorer


Theorem sectss

Description: The section relation is a relation between morphisms from X to Y and morphisms from Y to X . (Contributed by Mario Carneiro, 2-Jan-2017)

Ref Expression
Hypotheses issect.b ⊢ B = Base C
issect.h ⊢ H = Hom ⁡ C
issect.o ⊢ · ˙ = comp ⁡ C
issect.i ⊢ 1 ˙ = Id ⁡ C
issect.s ⊢ S = Sect ⁡ C
issect.c ⊢ φ → C ∈ Cat
issect.x ⊢ φ → X ∈ B
issect.y ⊢ φ → Y ∈ B
Assertion sectss ⊢ φ → X S Y ⊆ X H Y × Y H X

Proof

Step Hyp Ref Expression
1 issect.b ⊢ B = Base C
2 issect.h ⊢ H = Hom ⁡ C
3 issect.o ⊢ · ˙ = comp ⁡ C
4 issect.i ⊢ 1 ˙ = Id ⁡ C
5 issect.s ⊢ S = Sect ⁡ C
6 issect.c ⊢ φ → C ∈ Cat
7 issect.x ⊢ φ → X ∈ B
8 issect.y ⊢ φ → Y ∈ B
9 1 2 3 4 5 6 7 8 sectfval ⊢ φ → X S Y = f g | f ∈ X H Y ∧ g ∈ Y H X ∧ g X Y · ˙ X f = 1 ˙ ⁡ X
10 opabssxp ⊢ f g | f ∈ X H Y ∧ g ∈ Y H X ∧ g X Y · ˙ X f = 1 ˙ ⁡ X ⊆ X H Y × Y H X
11 9 10 eqsstrdi ⊢ φ → X S Y ⊆ X H Y × Y H X