Metamath Proof Explorer


Theorem shsval2i

Description: An alternate way to express subspace sum. (Contributed by NM, 25-Nov-2004) (New usage is discouraged.)

Ref Expression
Hypotheses shlesb1.1 ⊢ A ∈ S ℋ
shlesb1.2 ⊢ B ∈ S ℋ
Assertion shsval2i ⊢ A + ℋ B = ⋂ x ∈ S ℋ | A ∪ B ⊆ x

Proof

Step Hyp Ref Expression
1 shlesb1.1 ⊢ A ∈ S ℋ
2 shlesb1.2 ⊢ B ∈ S ℋ
3 ssun1 ⊢ A ⊆ A ∪ B
4 ssintub ⊢ A ∪ B ⊆ ⋂ x ∈ S ℋ | A ∪ B ⊆ x
5 3 4 sstri ⊢ A ⊆ ⋂ x ∈ S ℋ | A ∪ B ⊆ x
6 ssun2 ⊢ B ⊆ A ∪ B
7 6 4 sstri ⊢ B ⊆ ⋂ x ∈ S ℋ | A ∪ B ⊆ x
8 5 7 pm3.2i ⊢ A ⊆ ⋂ x ∈ S ℋ | A ∪ B ⊆ x ∧ B ⊆ ⋂ x ∈ S ℋ | A ∪ B ⊆ x
9 ssrab2 ⊢ x ∈ S ℋ | A ∪ B ⊆ x ⊆ S ℋ
10 1 2 shscli ⊢ A + ℋ B ∈ S ℋ
11 1 2 shunssi ⊢ A ∪ B ⊆ A + ℋ B
12 sseq2 ⊢ x = A + ℋ B → A ∪ B ⊆ x ↔ A ∪ B ⊆ A + ℋ B
13 12 rspcev ⊢ A + ℋ B ∈ S ℋ ∧ A ∪ B ⊆ A + ℋ B → ∃ x ∈ S ℋ A ∪ B ⊆ x
14 10 11 13 mp2an ⊢ ∃ x ∈ S ℋ A ∪ B ⊆ x
15 rabn0 ⊢ x ∈ S ℋ | A ∪ B ⊆ x ≠ ∅ ↔ ∃ x ∈ S ℋ A ∪ B ⊆ x
16 14 15 mpbir ⊢ x ∈ S ℋ | A ∪ B ⊆ x ≠ ∅
17 shintcl ⊢ x ∈ S ℋ | A ∪ B ⊆ x ⊆ S ℋ ∧ x ∈ S ℋ | A ∪ B ⊆ x ≠ ∅ → ⋂ x ∈ S ℋ | A ∪ B ⊆ x ∈ S ℋ
18 9 16 17 mp2an ⊢ ⋂ x ∈ S ℋ | A ∪ B ⊆ x ∈ S ℋ
19 1 2 18 shslubi ⊢ A ⊆ ⋂ x ∈ S ℋ | A ∪ B ⊆ x ∧ B ⊆ ⋂ x ∈ S ℋ | A ∪ B ⊆ x ↔ A + ℋ B ⊆ ⋂ x ∈ S ℋ | A ∪ B ⊆ x
20 8 19 mpbi ⊢ A + ℋ B ⊆ ⋂ x ∈ S ℋ | A ∪ B ⊆ x
21 12 elrab ⊢ A + ℋ B ∈ x ∈ S ℋ | A ∪ B ⊆ x ↔ A + ℋ B ∈ S ℋ ∧ A ∪ B ⊆ A + ℋ B
22 10 11 21 mpbir2an ⊢ A + ℋ B ∈ x ∈ S ℋ | A ∪ B ⊆ x
23 intss1 ⊢ A + ℋ B ∈ x ∈ S ℋ | A ∪ B ⊆ x → ⋂ x ∈ S ℋ | A ∪ B ⊆ x ⊆ A + ℋ B
24 22 23 ax-mp ⊢ ⋂ x ∈ S ℋ | A ∪ B ⊆ x ⊆ A + ℋ B
25 20 24 eqssi ⊢ A + ℋ B = ⋂ x ∈ S ℋ | A ∪ B ⊆ x