Metamath Proof Explorer


Theorem simpgnsgeqd

Description: A normal subgroup of a simple group is either the whole group or the trivial subgroup. (Contributed by Rohan Ridenour, 3-Aug-2023)

Ref Expression
Hypotheses simpgnsgeqd.1 ⊢ B = Base G
simpgnsgeqd.2 ⊢ 0 ˙ = 0 G
simpgnsgeqd.3 ⊢ φ → G ∈ SimpGrp
simpgnsgeqd.4 ⊢ φ → A ∈ NrmSGrp ⁡ G
Assertion simpgnsgeqd ⊢ φ → A = 0 ˙ ∨ A = B

Proof

Step Hyp Ref Expression
1 simpgnsgeqd.1 ⊢ B = Base G
2 simpgnsgeqd.2 ⊢ 0 ˙ = 0 G
3 simpgnsgeqd.3 ⊢ φ → G ∈ SimpGrp
4 simpgnsgeqd.4 ⊢ φ → A ∈ NrmSGrp ⁡ G
5 1 2 3 simpgnsgd ⊢ φ → NrmSGrp ⁡ G = 0 ˙ B
6 4 5 eleqtrd ⊢ φ → A ∈ 0 ˙ B
7 elpri ⊢ A ∈ 0 ˙ B → A = 0 ˙ ∨ A = B
8 6 7 syl ⊢ φ → A = 0 ˙ ∨ A = B