Metamath Proof Explorer


Theorem sqabsadd

Description: Square of absolute value of sum. Proposition 10-3.7(g) of Gleason p. 133. (Contributed by NM, 21-Jan-2007)

Ref Expression
Assertion sqabsadd ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B 2 = A 2 + B 2 + 2 ⁢ ℜ ⁡ A ⁢ B ‾

Proof

Step Hyp Ref Expression
1 cjadd ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B ‾ = A ‾ + B ‾
2 1 oveq2d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B ⁢ A + B ‾ = A + B ⁢ A ‾ + B ‾
3 cjcl ⊢ A ∈ ℂ → A ‾ ∈ ℂ
4 cjcl ⊢ B ∈ ℂ → B ‾ ∈ ℂ
5 3 4 anim12i ⊢ A ∈ ℂ ∧ B ∈ ℂ → A ‾ ∈ ℂ ∧ B ‾ ∈ ℂ
6 muladd ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ A ‾ ∈ ℂ ∧ B ‾ ∈ ℂ → A + B ⁢ A ‾ + B ‾ = A ⁢ A ‾ + B ‾ ⁢ B + A ⁢ B ‾ + A ‾ ⁢ B
7 5 6 mpdan ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B ⁢ A ‾ + B ‾ = A ⁢ A ‾ + B ‾ ⁢ B + A ⁢ B ‾ + A ‾ ⁢ B
8 2 7 eqtrd ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B ⁢ A + B ‾ = A ⁢ A ‾ + B ‾ ⁢ B + A ⁢ B ‾ + A ‾ ⁢ B
9 addcl ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B ∈ ℂ
10 absvalsq ⊢ A + B ∈ ℂ → A + B 2 = A + B ⁢ A + B ‾
11 9 10 syl ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B 2 = A + B ⁢ A + B ‾
12 absvalsq ⊢ A ∈ ℂ → A 2 = A ⁢ A ‾
13 absvalsq ⊢ B ∈ ℂ → B 2 = B ⁢ B ‾
14 mulcom ⊢ B ∈ ℂ ∧ B ‾ ∈ ℂ → B ⁢ B ‾ = B ‾ ⁢ B
15 4 14 mpdan ⊢ B ∈ ℂ → B ⁢ B ‾ = B ‾ ⁢ B
16 13 15 eqtrd ⊢ B ∈ ℂ → B 2 = B ‾ ⁢ B
17 12 16 oveqan12d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 2 + B 2 = A ⁢ A ‾ + B ‾ ⁢ B
18 mulcl ⊢ A ∈ ℂ ∧ B ‾ ∈ ℂ → A ⁢ B ‾ ∈ ℂ
19 4 18 sylan2 ⊢ A ∈ ℂ ∧ B ∈ ℂ → A ⁢ B ‾ ∈ ℂ
20 19 addcjd ⊢ A ∈ ℂ ∧ B ∈ ℂ → A ⁢ B ‾ + A ⁢ B ‾ ‾ = 2 ⁢ ℜ ⁡ A ⁢ B ‾
21 cjmul ⊢ A ∈ ℂ ∧ B ‾ ∈ ℂ → A ⁢ B ‾ ‾ = A ‾ ⁢ B ‾ ‾
22 4 21 sylan2 ⊢ A ∈ ℂ ∧ B ∈ ℂ → A ⁢ B ‾ ‾ = A ‾ ⁢ B ‾ ‾
23 cjcj ⊢ B ∈ ℂ → B ‾ ‾ = B
24 23 adantl ⊢ A ∈ ℂ ∧ B ∈ ℂ → B ‾ ‾ = B
25 24 oveq2d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A ‾ ⁢ B ‾ ‾ = A ‾ ⁢ B
26 22 25 eqtrd ⊢ A ∈ ℂ ∧ B ∈ ℂ → A ⁢ B ‾ ‾ = A ‾ ⁢ B
27 26 oveq2d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A ⁢ B ‾ + A ⁢ B ‾ ‾ = A ⁢ B ‾ + A ‾ ⁢ B
28 20 27 eqtr3d ⊢ A ∈ ℂ ∧ B ∈ ℂ → 2 ⁢ ℜ ⁡ A ⁢ B ‾ = A ⁢ B ‾ + A ‾ ⁢ B
29 17 28 oveq12d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 2 + B 2 + 2 ⁢ ℜ ⁡ A ⁢ B ‾ = A ⁢ A ‾ + B ‾ ⁢ B + A ⁢ B ‾ + A ‾ ⁢ B
30 8 11 29 3eqtr4d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B 2 = A 2 + B 2 + 2 ⁢ ℜ ⁡ A ⁢ B ‾