Metamath Proof Explorer


Theorem sqrtcvallem4

Description: Equivalent to saying that the square of the real component of the square root of a complex number is a nonnegative real number. Lemma for sqrtcval . See resqrtval . (Contributed by RP, 11-May-2024)

Ref Expression
Assertion sqrtcvallem4 ⊢ A ∈ ℂ → 0 ≤ A + ℜ ⁡ A 2

Proof

Step Hyp Ref Expression
1 abscl ⊢ A ∈ ℂ → A ∈ ℝ
2 recl ⊢ A ∈ ℂ → ℜ ⁡ A ∈ ℝ
3 1 2 readdcld ⊢ A ∈ ℂ → A + ℜ ⁡ A ∈ ℝ
4 2rp ⊢ 2 ∈ ℝ +
5 4 a1i ⊢ A ∈ ℂ → 2 ∈ ℝ +
6 negcl ⊢ A ∈ ℂ → − A ∈ ℂ
7 6 releabsd ⊢ A ∈ ℂ → ℜ ⁡ − A ≤ − A
8 6 abscld ⊢ A ∈ ℂ → − A ∈ ℝ
9 6 recld ⊢ A ∈ ℂ → ℜ ⁡ − A ∈ ℝ
10 8 9 subge0d ⊢ A ∈ ℂ → 0 ≤ − A − ℜ ⁡ − A ↔ ℜ ⁡ − A ≤ − A
11 7 10 mpbird ⊢ A ∈ ℂ → 0 ≤ − A − ℜ ⁡ − A
12 absneg ⊢ A ∈ ℂ → − A = A
13 reneg ⊢ A ∈ ℂ → ℜ ⁡ − A = − ℜ ⁡ A
14 12 13 oveq12d ⊢ A ∈ ℂ → − A − ℜ ⁡ − A = A − − ℜ ⁡ A
15 1 recnd ⊢ A ∈ ℂ → A ∈ ℂ
16 2 recnd ⊢ A ∈ ℂ → ℜ ⁡ A ∈ ℂ
17 15 16 subnegd ⊢ A ∈ ℂ → A − − ℜ ⁡ A = A + ℜ ⁡ A
18 14 17 eqtrd ⊢ A ∈ ℂ → − A − ℜ ⁡ − A = A + ℜ ⁡ A
19 11 18 breqtrd ⊢ A ∈ ℂ → 0 ≤ A + ℜ ⁡ A
20 3 5 19 divge0d ⊢ A ∈ ℂ → 0 ≤ A + ℜ ⁡ A 2