Metamath Proof Explorer


Theorem ssficl

Description: The class of all subsets of a class has the finite intersection property. (Contributed by RP, 1-Jan-2020) (Proof shortened by RP, 3-Jan-2020)

Ref Expression
Hypothesis ssficl.a ⊢ A = z | z ⊆ B
Assertion ssficl ⊢ ∀ x ∈ A ∀ y ∈ A x ∩ y ∈ A

Proof

Step Hyp Ref Expression
1 ssficl.a ⊢ A = z | z ⊆ B
2 vex ⊢ x ∈ V
3 2 inex1 ⊢ x ∩ y ∈ V
4 sseq1 ⊢ z = x ∩ y → z ⊆ B ↔ x ∩ y ⊆ B
5 sseq1 ⊢ z = x → z ⊆ B ↔ x ⊆ B
6 sseq1 ⊢ z = y → z ⊆ B ↔ y ⊆ B
7 ssinss1 ⊢ x ⊆ B → x ∩ y ⊆ B
8 7 adantr ⊢ x ⊆ B ∧ y ⊆ B → x ∩ y ⊆ B
9 1 3 4 5 6 8 cllem0 ⊢ ∀ x ∈ A ∀ y ∈ A x ∩ y ∈ A