Metamath Proof Explorer


Theorem suceqd

Description: Deduction associated with suceq . (Contributed by Rohan Ridenour, 8-Aug-2023)

Ref Expression
Hypothesis suceqd.1 φ A = B
Assertion suceqd φ suc A = suc B

Proof

Step Hyp Ref Expression
1 suceqd.1 φ A = B
2 suceq A = B suc A = suc B
3 1 2 syl φ suc A = suc B