Metamath Proof Explorer


Theorem tg5segofs

Description: Rephrase axtg5seg using the outer five segment predicate. Theorem 2.10 of Schwabhauser p. 28. (Contributed by Thierry Arnoux, 23-Mar-2019)

Ref Expression
Hypotheses tg5segofs.p ⊢ P = Base G
tg5segofs.m ⊢ - ˙ = dist ⁡ G
tg5segofs.s ⊢ I = Itv ⁡ G
tg5segofs.g ⊢ φ → G ∈ 𝒢 Tarski
tg5segofs.a ⊢ φ → A ∈ P
tg5segofs.b ⊢ φ → B ∈ P
tg5segofs.c ⊢ φ → C ∈ P
tg5segofs.d ⊢ φ → D ∈ P
tg5segofs.e ⊢ φ → E ∈ P
tg5segofs.f ⊢ φ → F ∈ P
tg5segofs.o ⊢ O = AFS ⁡ G
tg5segofs.h ⊢ φ → H ∈ P
tg5segofs.i ⊢ φ → I ∈ P
tg5segofs.1 ⊢ φ → A B C D O E F H I
tg5segofs.2 ⊢ φ → A ≠ B
Assertion tg5segofs ⊢ φ → C - ˙ D = H - ˙ I

Proof

Step Hyp Ref Expression
1 tg5segofs.p ⊢ P = Base G
2 tg5segofs.m ⊢ - ˙ = dist ⁡ G
3 tg5segofs.s ⊢ I = Itv ⁡ G
4 tg5segofs.g ⊢ φ → G ∈ 𝒢 Tarski
5 tg5segofs.a ⊢ φ → A ∈ P
6 tg5segofs.b ⊢ φ → B ∈ P
7 tg5segofs.c ⊢ φ → C ∈ P
8 tg5segofs.d ⊢ φ → D ∈ P
9 tg5segofs.e ⊢ φ → E ∈ P
10 tg5segofs.f ⊢ φ → F ∈ P
11 tg5segofs.o ⊢ O = AFS ⁡ G
12 tg5segofs.h ⊢ φ → H ∈ P
13 tg5segofs.i ⊢ φ → I ∈ P
14 tg5segofs.1 ⊢ φ → A B C D O E F H I
15 tg5segofs.2 ⊢ φ → A ≠ B
16 1 2 3 4 11 5 6 7 8 9 10 12 13 brafs ⊢ φ → A B C D O E F H I ↔ B ∈ A I C ∧ F ∈ E I H ∧ A - ˙ B = E - ˙ F ∧ B - ˙ C = F - ˙ H ∧ A - ˙ D = E - ˙ I ∧ B - ˙ D = F - ˙ I
17 14 16 mpbid ⊢ φ → B ∈ A I C ∧ F ∈ E I H ∧ A - ˙ B = E - ˙ F ∧ B - ˙ C = F - ˙ H ∧ A - ˙ D = E - ˙ I ∧ B - ˙ D = F - ˙ I
18 17 simp1d ⊢ φ → B ∈ A I C ∧ F ∈ E I H
19 18 simpld ⊢ φ → B ∈ A I C
20 18 simprd ⊢ φ → F ∈ E I H
21 17 simp2d ⊢ φ → A - ˙ B = E - ˙ F ∧ B - ˙ C = F - ˙ H
22 21 simpld ⊢ φ → A - ˙ B = E - ˙ F
23 21 simprd ⊢ φ → B - ˙ C = F - ˙ H
24 17 simp3d ⊢ φ → A - ˙ D = E - ˙ I ∧ B - ˙ D = F - ˙ I
25 24 simpld ⊢ φ → A - ˙ D = E - ˙ I
26 24 simprd ⊢ φ → B - ˙ D = F - ˙ I
27 1 2 3 4 5 6 7 9 10 12 8 13 15 19 20 22 23 25 26 axtg5seg ⊢ φ → C - ˙ D = H - ˙ I