Metamath Proof Explorer


Theorem tposfun

Description: The transposition of a function is a function. (Contributed by Mario Carneiro, 10-Sep-2015)

Ref Expression
Assertion tposfun ⊢ Fun ⁡ F → Fun ⁡ tpos F

Proof

Step Hyp Ref Expression
1 funmpt ⊢ Fun ⁡ x ∈ dom ⁡ F -1 ∪ ∅ ⟼ ⋃ x -1
2 funco ⊢ Fun ⁡ F ∧ Fun ⁡ x ∈ dom ⁡ F -1 ∪ ∅ ⟼ ⋃ x -1 → Fun ⁡ F ∘ x ∈ dom ⁡ F -1 ∪ ∅ ⟼ ⋃ x -1
3 1 2 mpan2 ⊢ Fun ⁡ F → Fun ⁡ F ∘ x ∈ dom ⁡ F -1 ∪ ∅ ⟼ ⋃ x -1
4 df-tpos ⊢ tpos F = F ∘ x ∈ dom ⁡ F -1 ∪ ∅ ⟼ ⋃ x -1
5 4 funeqi ⊢ Fun ⁡ tpos F ↔ Fun ⁡ F ∘ x ∈ dom ⁡ F -1 ∪ ∅ ⟼ ⋃ x -1
6 3 5 sylibr ⊢ Fun ⁡ F → Fun ⁡ tpos F