Metamath Proof Explorer


Theorem trlnidatb

Description: A lattice translation is not the identity iff its trace is an atom. TODO: Can proofs be reorganized so this goes with trlnidat ? Why do both this and ltrnideq need trlnidat ? (Contributed by NM, 4-Jun-2013)

Ref Expression
Hypotheses trlnidatb.b ⊢ B = Base K
trlnidatb.a ⊢ A = Atoms ⁡ K
trlnidatb.h ⊢ H = LHyp ⁡ K
trlnidatb.t ⊢ T = LTrn ⁡ K ⁡ W
trlnidatb.r ⊢ R = trL ⁡ K ⁡ W
Assertion trlnidatb ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T → F ≠ I ↾ B ↔ R ⁡ F ∈ A

Proof

Step Hyp Ref Expression
1 trlnidatb.b ⊢ B = Base K
2 trlnidatb.a ⊢ A = Atoms ⁡ K
3 trlnidatb.h ⊢ H = LHyp ⁡ K
4 trlnidatb.t ⊢ T = LTrn ⁡ K ⁡ W
5 trlnidatb.r ⊢ R = trL ⁡ K ⁡ W
6 1 2 3 4 5 trlnidat ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B → R ⁡ F ∈ A
7 6 3expia ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T → F ≠ I ↾ B → R ⁡ F ∈ A
8 eqid ⊢ ≤ K = ≤ K
9 8 2 3 lhpexnle ⊢ K ∈ HL ∧ W ∈ H → ∃ p ∈ A ¬ p ≤ K W
10 9 adantr ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T → ∃ p ∈ A ¬ p ≤ K W
11 1 8 2 3 4 ltrnideq ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ p ∈ A ∧ ¬ p ≤ K W → F = I ↾ B ↔ F ⁡ p = p
12 11 3expa ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ p ∈ A ∧ ¬ p ≤ K W → F = I ↾ B ↔ F ⁡ p = p
13 simp1l ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ p ∈ A ∧ ¬ p ≤ K W ∧ F ⁡ p = p → K ∈ HL ∧ W ∈ H
14 simp2 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ p ∈ A ∧ ¬ p ≤ K W ∧ F ⁡ p = p → p ∈ A ∧ ¬ p ≤ K W
15 simp1r ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ p ∈ A ∧ ¬ p ≤ K W ∧ F ⁡ p = p → F ∈ T
16 simp3 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ p ∈ A ∧ ¬ p ≤ K W ∧ F ⁡ p = p → F ⁡ p = p
17 eqid ⊢ 0. ⁡ K = 0. ⁡ K
18 8 17 2 3 4 5 trl0 ⊢ K ∈ HL ∧ W ∈ H ∧ p ∈ A ∧ ¬ p ≤ K W ∧ F ∈ T ∧ F ⁡ p = p → R ⁡ F = 0. ⁡ K
19 13 14 15 16 18 syl112anc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ p ∈ A ∧ ¬ p ≤ K W ∧ F ⁡ p = p → R ⁡ F = 0. ⁡ K
20 19 3expia ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ p ∈ A ∧ ¬ p ≤ K W → F ⁡ p = p → R ⁡ F = 0. ⁡ K
21 simplll ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ p ∈ A ∧ ¬ p ≤ K W → K ∈ HL
22 hlatl ⊢ K ∈ HL → K ∈ AtLat
23 17 2 atn0 ⊢ K ∈ AtLat ∧ R ⁡ F ∈ A → R ⁡ F ≠ 0. ⁡ K
24 23 ex ⊢ K ∈ AtLat → R ⁡ F ∈ A → R ⁡ F ≠ 0. ⁡ K
25 21 22 24 3syl ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ p ∈ A ∧ ¬ p ≤ K W → R ⁡ F ∈ A → R ⁡ F ≠ 0. ⁡ K
26 25 necon2bd ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ p ∈ A ∧ ¬ p ≤ K W → R ⁡ F = 0. ⁡ K → ¬ R ⁡ F ∈ A
27 20 26 syld ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ p ∈ A ∧ ¬ p ≤ K W → F ⁡ p = p → ¬ R ⁡ F ∈ A
28 12 27 sylbid ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ p ∈ A ∧ ¬ p ≤ K W → F = I ↾ B → ¬ R ⁡ F ∈ A
29 10 28 rexlimddv ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T → F = I ↾ B → ¬ R ⁡ F ∈ A
30 29 necon2ad ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T → R ⁡ F ∈ A → F ≠ I ↾ B
31 7 30 impbid ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T → F ≠ I ↾ B ↔ R ⁡ F ∈ A