Metamath Proof Explorer


Theorem unceq

Description: Equality theorem for uncurrying. (Contributed by Brendan Leahy, 2-Jun-2021)

Ref Expression
Assertion unceq ⊢ A = B → uncurry A = uncurry B

Proof

Step Hyp Ref Expression
1 fveq1 ⊢ A = B → A ⁡ x = B ⁡ x
2 1 breqd ⊢ A = B → y A ⁡ x z ↔ y B ⁡ x z
3 2 oprabbidv ⊢ A = B → x y z | y A ⁡ x z = x y z | y B ⁡ x z
4 df-unc ⊢ uncurry A = x y z | y A ⁡ x z
5 df-unc ⊢ uncurry B = x y z | y B ⁡ x z
6 3 4 5 3eqtr4g ⊢ A = B → uncurry A = uncurry B