Metamath Proof Explorer


Theorem unssd

Description: A deduction showing the union of two subclasses is a subclass. (Contributed by Jonathan Ben-Naim, 3-Jun-2011)

Ref Expression
Hypotheses unssd.1 ⊢ φ → A ⊆ C
unssd.2 ⊢ φ → B ⊆ C
Assertion unssd ⊢ φ → A ∪ B ⊆ C

Proof

Step Hyp Ref Expression
1 unssd.1 ⊢ φ → A ⊆ C
2 unssd.2 ⊢ φ → B ⊆ C
3 unss ⊢ A ⊆ C ∧ B ⊆ C ↔ A ∪ B ⊆ C
4 3 biimpi ⊢ A ⊆ C ∧ B ⊆ C → A ∪ B ⊆ C
5 1 2 4 syl2anc ⊢ φ → A ∪ B ⊆ C