Metamath Proof Explorer


Theorem updjudhf

Description: The mapping of an element of the disjoint union to the value of the corresponding function is a function. (Contributed by AV, 26-Jun-2022)

Ref Expression
Hypotheses updjud.f ⊢ φ → F : A ⟶ C
updjud.g ⊢ φ → G : B ⟶ C
updjudhf.h ⊢ H = x ∈ A ⊔︀ B ⟼ if 1 st ⁡ x = ∅ F ⁡ 2 nd ⁡ x G ⁡ 2 nd ⁡ x
Assertion updjudhf ⊢ φ → H : A ⊔︀ B ⟶ C

Proof

Step Hyp Ref Expression
1 updjud.f ⊢ φ → F : A ⟶ C
2 updjud.g ⊢ φ → G : B ⟶ C
3 updjudhf.h ⊢ H = x ∈ A ⊔︀ B ⟼ if 1 st ⁡ x = ∅ F ⁡ 2 nd ⁡ x G ⁡ 2 nd ⁡ x
4 eldju2ndl ⊢ x ∈ A ⊔︀ B ∧ 1 st ⁡ x = ∅ → 2 nd ⁡ x ∈ A
5 4 ex ⊢ x ∈ A ⊔︀ B → 1 st ⁡ x = ∅ → 2 nd ⁡ x ∈ A
6 ffvelcdm ⊢ F : A ⟶ C ∧ 2 nd ⁡ x ∈ A → F ⁡ 2 nd ⁡ x ∈ C
7 6 ex ⊢ F : A ⟶ C → 2 nd ⁡ x ∈ A → F ⁡ 2 nd ⁡ x ∈ C
8 1 7 syl ⊢ φ → 2 nd ⁡ x ∈ A → F ⁡ 2 nd ⁡ x ∈ C
9 5 8 sylan9r ⊢ φ ∧ x ∈ A ⊔︀ B → 1 st ⁡ x = ∅ → F ⁡ 2 nd ⁡ x ∈ C
10 9 imp ⊢ φ ∧ x ∈ A ⊔︀ B ∧ 1 st ⁡ x = ∅ → F ⁡ 2 nd ⁡ x ∈ C
11 df-ne ⊢ 1 st ⁡ x ≠ ∅ ↔ ¬ 1 st ⁡ x = ∅
12 eldju2ndr ⊢ x ∈ A ⊔︀ B ∧ 1 st ⁡ x ≠ ∅ → 2 nd ⁡ x ∈ B
13 12 ex ⊢ x ∈ A ⊔︀ B → 1 st ⁡ x ≠ ∅ → 2 nd ⁡ x ∈ B
14 ffvelcdm ⊢ G : B ⟶ C ∧ 2 nd ⁡ x ∈ B → G ⁡ 2 nd ⁡ x ∈ C
15 14 ex ⊢ G : B ⟶ C → 2 nd ⁡ x ∈ B → G ⁡ 2 nd ⁡ x ∈ C
16 2 15 syl ⊢ φ → 2 nd ⁡ x ∈ B → G ⁡ 2 nd ⁡ x ∈ C
17 13 16 sylan9r ⊢ φ ∧ x ∈ A ⊔︀ B → 1 st ⁡ x ≠ ∅ → G ⁡ 2 nd ⁡ x ∈ C
18 11 17 biimtrrid ⊢ φ ∧ x ∈ A ⊔︀ B → ¬ 1 st ⁡ x = ∅ → G ⁡ 2 nd ⁡ x ∈ C
19 18 imp ⊢ φ ∧ x ∈ A ⊔︀ B ∧ ¬ 1 st ⁡ x = ∅ → G ⁡ 2 nd ⁡ x ∈ C
20 10 19 ifclda ⊢ φ ∧ x ∈ A ⊔︀ B → if 1 st ⁡ x = ∅ F ⁡ 2 nd ⁡ x G ⁡ 2 nd ⁡ x ∈ C
21 20 3 fmptd ⊢ φ → H : A ⊔︀ B ⟶ C