Metamath Proof Explorer


Theorem 420gcd8e4

Description: The gcd of 420 and 8 is 4. (Contributed by metakunt, 25-Apr-2024)

Ref Expression
Assertion 420gcd8e4 ( 4 2 0 gcd 8 ) = 4

Proof

Step Hyp Ref Expression
1 8nn ⊢ 8 ∈ ℕ
2 4nn ⊢ 4 ∈ ℕ
3 5nn0 ⊢ 5 ∈ ℕ0
4 2nn ⊢ 2 ∈ ℕ
5 3 4 decnncl ⊢ 5 2 ∈ ℕ
6 5 nnzi ⊢ 5 2 ∈ ℤ
7 1 2 6 gcdaddmzz2nncomi ⊢ ( 8 gcd 4 ) = ( 8 gcd ( ( 5 2 · 8 ) + 4 ) )
8 4nn0 ⊢ 4 ∈ ℕ0
9 1nn0 ⊢ 1 ∈ ℕ0
10 8 9 deccl ⊢ 4 1 ∈ ℕ0
11 6nn0 ⊢ 6 ∈ ℕ0
12 0nn0 ⊢ 0 ∈ ℕ0
13 eqid ⊢ 4 1 6 = 4 1 6
14 8 dec0h ⊢ 4 = 0 4
15 1p1e2 ⊢ ( 1 + 1 ) = 2
16 10 nn0cni ⊢ 4 1 ∈ ℂ
17 16 addridi ⊢ ( 4 1 + 0 ) = 4 1
18 8 9 15 17 decsuc ⊢ ( ( 4 1 + 0 ) + 1 ) = 4 2
19 6p4e10 ⊢ ( 6 + 4 ) = 1 0
20 10 11 12 8 13 14 18 19 decaddc2 ⊢ ( 4 1 6 + 4 ) = 4 2 0
21 8nn0 ⊢ 8 ∈ ℕ0
22 2nn0 ⊢ 2 ∈ ℕ0
23 eqid ⊢ 5 2 = 5 2
24 0p1e1 ⊢ ( 0 + 1 ) = 1
25 8t5e40 ⊢ ( 8 · 5 ) = 4 0
26 8 12 24 25 decsuc ⊢ ( ( 8 · 5 ) + 1 ) = 4 1
27 8t2e16 ⊢ ( 8 · 2 ) = 1 6
28 21 3 22 23 11 9 26 27 decmul2c ⊢ ( 8 · 5 2 ) = 4 1 6
29 1 5 mulcomnni ⊢ ( 8 · 5 2 ) = ( 5 2 · 8 )
30 28 29 eqtr3i ⊢ 4 1 6 = ( 5 2 · 8 )
31 30 oveq1i ⊢ ( 4 1 6 + 4 ) = ( ( 5 2 · 8 ) + 4 )
32 20 31 eqtr3i ⊢ 4 2 0 = ( ( 5 2 · 8 ) + 4 )
33 32 oveq2i ⊢ ( 8 gcd 4 2 0 ) = ( 8 gcd ( ( 5 2 · 8 ) + 4 ) )
34 7 33 eqtr4i ⊢ ( 8 gcd 4 ) = ( 8 gcd 4 2 0 )
35 1 2 gcdcomnni ⊢ ( 8 gcd 4 ) = ( 4 gcd 8 )
36 4t2e8 ⊢ ( 4 · 2 ) = 8
37 36 oveq2i ⊢ ( 4 gcd ( 4 · 2 ) ) = ( 4 gcd 8 )
38 2 4 gcdmultiplei ⊢ ( 4 gcd ( 4 · 2 ) ) = 4
39 37 38 eqtr3i ⊢ ( 4 gcd 8 ) = 4
40 35 39 eqtri ⊢ ( 8 gcd 4 ) = 4
41 8 4 decnncl ⊢ 4 2 ∈ ℕ
42 41 decnncl2 ⊢ 4 2 0 ∈ ℕ
43 1 42 gcdcomnni ⊢ ( 8 gcd 4 2 0 ) = ( 4 2 0 gcd 8 )
44 34 40 43 3eqtr3ri ⊢ ( 4 2 0 gcd 8 ) = 4