Metamath Proof Explorer


Theorem bi2anan9

Description: Deduction joining two equivalences to form equivalence of conjunctions. (Contributed by NM, 31-Jul-1995)

Ref Expression
Hypotheses bi2an9.1 ⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) )
bi2an9.2 ⊢ ( 𝜃 → ( 𝜏 ↔ 𝜂 ) )
Assertion bi2anan9 ( ( 𝜑 ∧ 𝜃 ) → ( ( 𝜓 ∧ 𝜏 ) ↔ ( 𝜒 ∧ 𝜂 ) ) )

Proof

Step Hyp Ref Expression
1 bi2an9.1 ⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) )
2 bi2an9.2 ⊢ ( 𝜃 → ( 𝜏 ↔ 𝜂 ) )
3 pm4.38 ⊢ ( ( ( 𝜓 ↔ 𝜒 ) ∧ ( 𝜏 ↔ 𝜂 ) ) → ( ( 𝜓 ∧ 𝜏 ) ↔ ( 𝜒 ∧ 𝜂 ) ) )
4 1 2 3 syl2an ⊢ ( ( 𝜑 ∧ 𝜃 ) → ( ( 𝜓 ∧ 𝜏 ) ↔ ( 𝜒 ∧ 𝜂 ) ) )