Metamath Proof Explorer


Theorem biadanid

Description: Deduction associated with biadani . Add a conjunction to an equivalence. (Contributed by Thierry Arnoux, 16-Jun-2024)

Ref Expression
Hypotheses biadanid.1 ⊢ ( ( 𝜑 ∧ 𝜓 ) → 𝜒 )
biadanid.2 ⊢ ( ( 𝜑 ∧ 𝜒 ) → ( 𝜓 ↔ 𝜃 ) )
Assertion biadanid ( 𝜑 → ( 𝜓 ↔ ( 𝜒 ∧ 𝜃 ) ) )

Proof

Step Hyp Ref Expression
1 biadanid.1 ⊢ ( ( 𝜑 ∧ 𝜓 ) → 𝜒 )
2 biadanid.2 ⊢ ( ( 𝜑 ∧ 𝜒 ) → ( 𝜓 ↔ 𝜃 ) )
3 2 biimpa ⊢ ( ( ( 𝜑 ∧ 𝜒 ) ∧ 𝜓 ) → 𝜃 )
4 3 an32s ⊢ ( ( ( 𝜑 ∧ 𝜓 ) ∧ 𝜒 ) → 𝜃 )
5 1 4 mpdan ⊢ ( ( 𝜑 ∧ 𝜓 ) → 𝜃 )
6 1 5 jca ⊢ ( ( 𝜑 ∧ 𝜓 ) → ( 𝜒 ∧ 𝜃 ) )
7 2 biimpar ⊢ ( ( ( 𝜑 ∧ 𝜒 ) ∧ 𝜃 ) → 𝜓 )
8 7 anasss ⊢ ( ( 𝜑 ∧ ( 𝜒 ∧ 𝜃 ) ) → 𝜓 )
9 6 8 impbida ⊢ ( 𝜑 → ( 𝜓 ↔ ( 𝜒 ∧ 𝜃 ) ) )