Metamath Proof Explorer


Theorem bnj981

Description: Technical lemma for bnj69 . This lemma may no longer be used or have become an indirect lemma of the theorem in question (i.e. a lemma of a lemma... of the theorem). (Contributed by Jonathan Ben-Naim, 3-Jun-2011) (New usage is discouraged.)

Ref Expression
Hypotheses bnj981.1 ⊢ ( 𝜑 ↔ ( 𝑓 ‘ ∅ ) = pred ( 𝑋 , 𝐴 , 𝑅 ) )
bnj981.2 ⊢ ( 𝜓 ↔ ∀ 𝑖 ∈ ω ( suc 𝑖 ∈ 𝑛 → ( 𝑓 ‘ suc 𝑖 ) = ∪ 𝑦 ∈ ( 𝑓 ‘ 𝑖 ) pred ( 𝑦 , 𝐴 , 𝑅 ) ) )
bnj981.3 ⊢ 𝐷 = ( ω ∖ { ∅ } )
bnj981.4 ⊢ 𝐵 = { 𝑓 ∣ ∃ 𝑛 ∈ 𝐷 ( 𝑓 Fn 𝑛 ∧ 𝜑 ∧ 𝜓 ) }
bnj981.5 ⊢ ( 𝜒 ↔ ( 𝑛 ∈ 𝐷 ∧ 𝑓 Fn 𝑛 ∧ 𝜑 ∧ 𝜓 ) )
Assertion bnj981 ( 𝑍 ∈ trCl ( 𝑋 , 𝐴 , 𝑅 ) → ∃ 𝑓 ∃ 𝑛 ∃ 𝑖 ( 𝜒 ∧ 𝑖 ∈ 𝑛 ∧ 𝑍 ∈ ( 𝑓 ‘ 𝑖 ) ) )

Proof

Step Hyp Ref Expression
1 bnj981.1 ⊢ ( 𝜑 ↔ ( 𝑓 ‘ ∅ ) = pred ( 𝑋 , 𝐴 , 𝑅 ) )
2 bnj981.2 ⊢ ( 𝜓 ↔ ∀ 𝑖 ∈ ω ( suc 𝑖 ∈ 𝑛 → ( 𝑓 ‘ suc 𝑖 ) = ∪ 𝑦 ∈ ( 𝑓 ‘ 𝑖 ) pred ( 𝑦 , 𝐴 , 𝑅 ) ) )
3 bnj981.3 ⊢ 𝐷 = ( ω ∖ { ∅ } )
4 bnj981.4 ⊢ 𝐵 = { 𝑓 ∣ ∃ 𝑛 ∈ 𝐷 ( 𝑓 Fn 𝑛 ∧ 𝜑 ∧ 𝜓 ) }
5 bnj981.5 ⊢ ( 𝜒 ↔ ( 𝑛 ∈ 𝐷 ∧ 𝑓 Fn 𝑛 ∧ 𝜑 ∧ 𝜓 ) )
6 nfv ⊢ Ⅎ 𝑦 𝑍 ∈ trCl ( 𝑋 , 𝐴 , 𝑅 )
7 nfcv ⊢ Ⅎ 𝑦 ω
8 nfv ⊢ Ⅎ 𝑦 suc 𝑖 ∈ 𝑛
9 nfiu1 ⊢ Ⅎ 𝑦 ∪ 𝑦 ∈ ( 𝑓 ‘ 𝑖 ) pred ( 𝑦 , 𝐴 , 𝑅 )
10 9 nfeq2 ⊢ Ⅎ 𝑦 ( 𝑓 ‘ suc 𝑖 ) = ∪ 𝑦 ∈ ( 𝑓 ‘ 𝑖 ) pred ( 𝑦 , 𝐴 , 𝑅 )
11 8 10 nfim ⊢ Ⅎ 𝑦 ( suc 𝑖 ∈ 𝑛 → ( 𝑓 ‘ suc 𝑖 ) = ∪ 𝑦 ∈ ( 𝑓 ‘ 𝑖 ) pred ( 𝑦 , 𝐴 , 𝑅 ) )
12 7 11 nfralw ⊢ Ⅎ 𝑦 ∀ 𝑖 ∈ ω ( suc 𝑖 ∈ 𝑛 → ( 𝑓 ‘ suc 𝑖 ) = ∪ 𝑦 ∈ ( 𝑓 ‘ 𝑖 ) pred ( 𝑦 , 𝐴 , 𝑅 ) )
13 2 12 nfxfr ⊢ Ⅎ 𝑦 𝜓
14 13 nf5ri ⊢ ( 𝜓 → ∀ 𝑦 𝜓 )
15 14 5 bnj1096 ⊢ ( 𝜒 → ∀ 𝑦 𝜒 )
16 15 nf5i ⊢ Ⅎ 𝑦 𝜒
17 nfv ⊢ Ⅎ 𝑦 𝑖 ∈ 𝑛
18 nfv ⊢ Ⅎ 𝑦 𝑍 ∈ ( 𝑓 ‘ 𝑖 )
19 16 17 18 nf3an ⊢ Ⅎ 𝑦 ( 𝜒 ∧ 𝑖 ∈ 𝑛 ∧ 𝑍 ∈ ( 𝑓 ‘ 𝑖 ) )
20 19 nfex ⊢ Ⅎ 𝑦 ∃ 𝑖 ( 𝜒 ∧ 𝑖 ∈ 𝑛 ∧ 𝑍 ∈ ( 𝑓 ‘ 𝑖 ) )
21 20 nfex ⊢ Ⅎ 𝑦 ∃ 𝑛 ∃ 𝑖 ( 𝜒 ∧ 𝑖 ∈ 𝑛 ∧ 𝑍 ∈ ( 𝑓 ‘ 𝑖 ) )
22 21 nfex ⊢ Ⅎ 𝑦 ∃ 𝑓 ∃ 𝑛 ∃ 𝑖 ( 𝜒 ∧ 𝑖 ∈ 𝑛 ∧ 𝑍 ∈ ( 𝑓 ‘ 𝑖 ) )
23 6 22 nfim ⊢ Ⅎ 𝑦 ( 𝑍 ∈ trCl ( 𝑋 , 𝐴 , 𝑅 ) → ∃ 𝑓 ∃ 𝑛 ∃ 𝑖 ( 𝜒 ∧ 𝑖 ∈ 𝑛 ∧ 𝑍 ∈ ( 𝑓 ‘ 𝑖 ) ) )
24 eleq1 ⊢ ( 𝑦 = 𝑍 → ( 𝑦 ∈ trCl ( 𝑋 , 𝐴 , 𝑅 ) ↔ 𝑍 ∈ trCl ( 𝑋 , 𝐴 , 𝑅 ) ) )
25 eleq1 ⊢ ( 𝑦 = 𝑍 → ( 𝑦 ∈ ( 𝑓 ‘ 𝑖 ) ↔ 𝑍 ∈ ( 𝑓 ‘ 𝑖 ) ) )
26 25 3anbi3d ⊢ ( 𝑦 = 𝑍 → ( ( 𝜒 ∧ 𝑖 ∈ 𝑛 ∧ 𝑦 ∈ ( 𝑓 ‘ 𝑖 ) ) ↔ ( 𝜒 ∧ 𝑖 ∈ 𝑛 ∧ 𝑍 ∈ ( 𝑓 ‘ 𝑖 ) ) ) )
27 26 3exbidv ⊢ ( 𝑦 = 𝑍 → ( ∃ 𝑓 ∃ 𝑛 ∃ 𝑖 ( 𝜒 ∧ 𝑖 ∈ 𝑛 ∧ 𝑦 ∈ ( 𝑓 ‘ 𝑖 ) ) ↔ ∃ 𝑓 ∃ 𝑛 ∃ 𝑖 ( 𝜒 ∧ 𝑖 ∈ 𝑛 ∧ 𝑍 ∈ ( 𝑓 ‘ 𝑖 ) ) ) )
28 24 27 imbi12d ⊢ ( 𝑦 = 𝑍 → ( ( 𝑦 ∈ trCl ( 𝑋 , 𝐴 , 𝑅 ) → ∃ 𝑓 ∃ 𝑛 ∃ 𝑖 ( 𝜒 ∧ 𝑖 ∈ 𝑛 ∧ 𝑦 ∈ ( 𝑓 ‘ 𝑖 ) ) ) ↔ ( 𝑍 ∈ trCl ( 𝑋 , 𝐴 , 𝑅 ) → ∃ 𝑓 ∃ 𝑛 ∃ 𝑖 ( 𝜒 ∧ 𝑖 ∈ 𝑛 ∧ 𝑍 ∈ ( 𝑓 ‘ 𝑖 ) ) ) ) )
29 1 2 3 4 5 bnj917 ⊢ ( 𝑦 ∈ trCl ( 𝑋 , 𝐴 , 𝑅 ) → ∃ 𝑓 ∃ 𝑛 ∃ 𝑖 ( 𝜒 ∧ 𝑖 ∈ 𝑛 ∧ 𝑦 ∈ ( 𝑓 ‘ 𝑖 ) ) )
30 23 28 29 vtoclg1f ⊢ ( 𝑍 ∈ trCl ( 𝑋 , 𝐴 , 𝑅 ) → ( 𝑍 ∈ trCl ( 𝑋 , 𝐴 , 𝑅 ) → ∃ 𝑓 ∃ 𝑛 ∃ 𝑖 ( 𝜒 ∧ 𝑖 ∈ 𝑛 ∧ 𝑍 ∈ ( 𝑓 ‘ 𝑖 ) ) ) )
31 30 pm2.43i ⊢ ( 𝑍 ∈ trCl ( 𝑋 , 𝐴 , 𝑅 ) → ∃ 𝑓 ∃ 𝑛 ∃ 𝑖 ( 𝜒 ∧ 𝑖 ∈ 𝑛 ∧ 𝑍 ∈ ( 𝑓 ‘ 𝑖 ) ) )