Metamath Proof Explorer


Theorem braew

Description: 'almost everywhere' relation for a measure M and a property ph (Contributed by Thierry Arnoux, 20-Oct-2017)

Ref Expression
Hypothesis braew.1 ⊢ ∪ dom 𝑀 = 𝑂
Assertion braew ( 𝑀 ∈ ∪ ran measures → ( { 𝑥 ∈ 𝑂 ∣ 𝜑 } a.e. 𝑀 ↔ ( 𝑀 ‘ { 𝑥 ∈ 𝑂 ∣ ¬ 𝜑 } ) = 0 ) )

Proof

Step Hyp Ref Expression
1 braew.1 ⊢ ∪ dom 𝑀 = 𝑂
2 dmexg ⊢ ( 𝑀 ∈ ∪ ran measures → dom 𝑀 ∈ V )
3 2 uniexd ⊢ ( 𝑀 ∈ ∪ ran measures → ∪ dom 𝑀 ∈ V )
4 1 3 eqeltrrid ⊢ ( 𝑀 ∈ ∪ ran measures → 𝑂 ∈ V )
5 rabexg ⊢ ( 𝑂 ∈ V → { 𝑥 ∈ 𝑂 ∣ 𝜑 } ∈ V )
6 4 5 syl ⊢ ( 𝑀 ∈ ∪ ran measures → { 𝑥 ∈ 𝑂 ∣ 𝜑 } ∈ V )
7 simpr ⊢ ( ( 𝑎 = { 𝑥 ∈ 𝑂 ∣ 𝜑 } ∧ 𝑚 = 𝑀 ) → 𝑚 = 𝑀 )
8 7 dmeqd ⊢ ( ( 𝑎 = { 𝑥 ∈ 𝑂 ∣ 𝜑 } ∧ 𝑚 = 𝑀 ) → dom 𝑚 = dom 𝑀 )
9 8 unieqd ⊢ ( ( 𝑎 = { 𝑥 ∈ 𝑂 ∣ 𝜑 } ∧ 𝑚 = 𝑀 ) → ∪ dom 𝑚 = ∪ dom 𝑀 )
10 simpl ⊢ ( ( 𝑎 = { 𝑥 ∈ 𝑂 ∣ 𝜑 } ∧ 𝑚 = 𝑀 ) → 𝑎 = { 𝑥 ∈ 𝑂 ∣ 𝜑 } )
11 9 10 difeq12d ⊢ ( ( 𝑎 = { 𝑥 ∈ 𝑂 ∣ 𝜑 } ∧ 𝑚 = 𝑀 ) → ( ∪ dom 𝑚 ∖ 𝑎 ) = ( ∪ dom 𝑀 ∖ { 𝑥 ∈ 𝑂 ∣ 𝜑 } ) )
12 7 11 fveq12d ⊢ ( ( 𝑎 = { 𝑥 ∈ 𝑂 ∣ 𝜑 } ∧ 𝑚 = 𝑀 ) → ( 𝑚 ‘ ( ∪ dom 𝑚 ∖ 𝑎 ) ) = ( 𝑀 ‘ ( ∪ dom 𝑀 ∖ { 𝑥 ∈ 𝑂 ∣ 𝜑 } ) ) )
13 12 eqeq1d ⊢ ( ( 𝑎 = { 𝑥 ∈ 𝑂 ∣ 𝜑 } ∧ 𝑚 = 𝑀 ) → ( ( 𝑚 ‘ ( ∪ dom 𝑚 ∖ 𝑎 ) ) = 0 ↔ ( 𝑀 ‘ ( ∪ dom 𝑀 ∖ { 𝑥 ∈ 𝑂 ∣ 𝜑 } ) ) = 0 ) )
14 df-ae ⊢ a.e. = { ⟨ 𝑎 , 𝑚 ⟩ ∣ ( 𝑚 ‘ ( ∪ dom 𝑚 ∖ 𝑎 ) ) = 0 }
15 13 14 brabga ⊢ ( ( { 𝑥 ∈ 𝑂 ∣ 𝜑 } ∈ V ∧ 𝑀 ∈ ∪ ran measures ) → ( { 𝑥 ∈ 𝑂 ∣ 𝜑 } a.e. 𝑀 ↔ ( 𝑀 ‘ ( ∪ dom 𝑀 ∖ { 𝑥 ∈ 𝑂 ∣ 𝜑 } ) ) = 0 ) )
16 6 15 mpancom ⊢ ( 𝑀 ∈ ∪ ran measures → ( { 𝑥 ∈ 𝑂 ∣ 𝜑 } a.e. 𝑀 ↔ ( 𝑀 ‘ ( ∪ dom 𝑀 ∖ { 𝑥 ∈ 𝑂 ∣ 𝜑 } ) ) = 0 ) )
17 1 difeq1i ⊢ ( ∪ dom 𝑀 ∖ { 𝑥 ∈ 𝑂 ∣ 𝜑 } ) = ( 𝑂 ∖ { 𝑥 ∈ 𝑂 ∣ 𝜑 } )
18 notrab ⊢ ( 𝑂 ∖ { 𝑥 ∈ 𝑂 ∣ 𝜑 } ) = { 𝑥 ∈ 𝑂 ∣ ¬ 𝜑 }
19 17 18 eqtri ⊢ ( ∪ dom 𝑀 ∖ { 𝑥 ∈ 𝑂 ∣ 𝜑 } ) = { 𝑥 ∈ 𝑂 ∣ ¬ 𝜑 }
20 19 fveq2i ⊢ ( 𝑀 ‘ ( ∪ dom 𝑀 ∖ { 𝑥 ∈ 𝑂 ∣ 𝜑 } ) ) = ( 𝑀 ‘ { 𝑥 ∈ 𝑂 ∣ ¬ 𝜑 } )
21 20 eqeq1i ⊢ ( ( 𝑀 ‘ ( ∪ dom 𝑀 ∖ { 𝑥 ∈ 𝑂 ∣ 𝜑 } ) ) = 0 ↔ ( 𝑀 ‘ { 𝑥 ∈ 𝑂 ∣ ¬ 𝜑 } ) = 0 )
22 16 21 bitrdi ⊢ ( 𝑀 ∈ ∪ ran measures → ( { 𝑥 ∈ 𝑂 ∣ 𝜑 } a.e. 𝑀 ↔ ( 𝑀 ‘ { 𝑥 ∈ 𝑂 ∣ ¬ 𝜑 } ) = 0 ) )