Metamath Proof Explorer


Theorem breng

Description: Equinumerosity relation. This variation of bren does not require the Axiom of Union. (Contributed by NM, 15-Jun-1998) Extract from a subproof of bren . (Revised by BTernaryTau, 23-Sep-2024)

Ref Expression
Assertion breng ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) → ( 𝐴 ≈ 𝐵 ↔ ∃ 𝑓 𝑓 : 𝐴 –1-1-onto→ 𝐵 ) )

Proof

Step Hyp Ref Expression
1 f1oeq2 ⊢ ( 𝑥 = 𝐴 → ( 𝑓 : 𝑥 –1-1-onto→ 𝑦 ↔ 𝑓 : 𝐴 –1-1-onto→ 𝑦 ) )
2 1 exbidv ⊢ ( 𝑥 = 𝐴 → ( ∃ 𝑓 𝑓 : 𝑥 –1-1-onto→ 𝑦 ↔ ∃ 𝑓 𝑓 : 𝐴 –1-1-onto→ 𝑦 ) )
3 f1oeq3 ⊢ ( 𝑦 = 𝐵 → ( 𝑓 : 𝐴 –1-1-onto→ 𝑦 ↔ 𝑓 : 𝐴 –1-1-onto→ 𝐵 ) )
4 3 exbidv ⊢ ( 𝑦 = 𝐵 → ( ∃ 𝑓 𝑓 : 𝐴 –1-1-onto→ 𝑦 ↔ ∃ 𝑓 𝑓 : 𝐴 –1-1-onto→ 𝐵 ) )
5 df-en ⊢ ≈ = { ⟨ 𝑥 , 𝑦 ⟩ ∣ ∃ 𝑓 𝑓 : 𝑥 –1-1-onto→ 𝑦 }
6 2 4 5 brabg ⊢ ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) → ( 𝐴 ≈ 𝐵 ↔ ∃ 𝑓 𝑓 : 𝐴 –1-1-onto→ 𝐵 ) )