Metamath Proof Explorer


Theorem cbvcsbdavw

Description: Change bound variable of a proper substitution into a class. Deduction form. (Contributed by GG, 14-Aug-2025)

Ref Expression
Hypothesis cbvcsbdavw.1 ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → 𝐵 = 𝐶 )
Assertion cbvcsbdavw ( 𝜑 → ⦋ 𝐴 / 𝑥 ⦌ 𝐵 = ⦋ 𝐴 / 𝑦 ⦌ 𝐶 )

Proof

Step Hyp Ref Expression
1 cbvcsbdavw.1 ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → 𝐵 = 𝐶 )
2 1 eleq2d ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → ( 𝑡 ∈ 𝐵 ↔ 𝑡 ∈ 𝐶 ) )
3 2 cbvsbcdavw ⊢ ( 𝜑 → ( [ 𝐴 / 𝑥 ] 𝑡 ∈ 𝐵 ↔ [ 𝐴 / 𝑦 ] 𝑡 ∈ 𝐶 ) )
4 3 abbidv ⊢ ( 𝜑 → { 𝑡 ∣ [ 𝐴 / 𝑥 ] 𝑡 ∈ 𝐵 } = { 𝑡 ∣ [ 𝐴 / 𝑦 ] 𝑡 ∈ 𝐶 } )
5 df-csb ⊢ ⦋ 𝐴 / 𝑥 ⦌ 𝐵 = { 𝑡 ∣ [ 𝐴 / 𝑥 ] 𝑡 ∈ 𝐵 }
6 df-csb ⊢ ⦋ 𝐴 / 𝑦 ⦌ 𝐶 = { 𝑡 ∣ [ 𝐴 / 𝑦 ] 𝑡 ∈ 𝐶 }
7 4 5 6 3eqtr4g ⊢ ( 𝜑 → ⦋ 𝐴 / 𝑥 ⦌ 𝐵 = ⦋ 𝐴 / 𝑦 ⦌ 𝐶 )