Metamath Proof Explorer


Theorem cbvmodavw

Description: Change bound variable in the at-most-one quantifier. Deduction form. (Contributed by GG, 14-Aug-2025)

Ref Expression
Hypothesis cbvmodavw.1 ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → ( 𝜓 ↔ 𝜒 ) )
Assertion cbvmodavw ( 𝜑 → ( ∃* 𝑥 𝜓 ↔ ∃* 𝑦 𝜒 ) )

Proof

Step Hyp Ref Expression
1 cbvmodavw.1 ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → ( 𝜓 ↔ 𝜒 ) )
2 equequ1 ⊢ ( 𝑥 = 𝑦 → ( 𝑥 = 𝑧 ↔ 𝑦 = 𝑧 ) )
3 2 adantl ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → ( 𝑥 = 𝑧 ↔ 𝑦 = 𝑧 ) )
4 1 3 imbi12d ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → ( ( 𝜓 → 𝑥 = 𝑧 ) ↔ ( 𝜒 → 𝑦 = 𝑧 ) ) )
5 4 cbvaldvaw ⊢ ( 𝜑 → ( ∀ 𝑥 ( 𝜓 → 𝑥 = 𝑧 ) ↔ ∀ 𝑦 ( 𝜒 → 𝑦 = 𝑧 ) ) )
6 5 exbidv ⊢ ( 𝜑 → ( ∃ 𝑧 ∀ 𝑥 ( 𝜓 → 𝑥 = 𝑧 ) ↔ ∃ 𝑧 ∀ 𝑦 ( 𝜒 → 𝑦 = 𝑧 ) ) )
7 dfmo ⊢ ( ∃* 𝑥 𝜓 ↔ ∃ 𝑧 ∀ 𝑥 ( 𝜓 → 𝑥 = 𝑧 ) )
8 dfmo ⊢ ( ∃* 𝑦 𝜒 ↔ ∃ 𝑧 ∀ 𝑦 ( 𝜒 → 𝑦 = 𝑧 ) )
9 6 7 8 3bitr4g ⊢ ( 𝜑 → ( ∃* 𝑥 𝜓 ↔ ∃* 𝑦 𝜒 ) )