Metamath Proof Explorer


Theorem cbvsbcdavw2

Description: Change bound variable of a class substitution. General version of cbvsbcdavw . Deduction form. (Contributed by GG, 14-Aug-2025)

Ref Expression
Hypotheses cbvsbcdavw2.1 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
cbvsbcdavw2.2 ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → ( 𝜓 ↔ 𝜒 ) )
Assertion cbvsbcdavw2 ( 𝜑 → ( [ 𝐴 / 𝑥 ] 𝜓 ↔ [ 𝐵 / 𝑦 ] 𝜒 ) )

Proof

Step Hyp Ref Expression
1 cbvsbcdavw2.1 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
2 cbvsbcdavw2.2 ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → ( 𝜓 ↔ 𝜒 ) )
3 2 cbvabdavw ⊢ ( 𝜑 → { 𝑥 ∣ 𝜓 } = { 𝑦 ∣ 𝜒 } )
4 1 3 eleq12d ⊢ ( 𝜑 → ( 𝐴 ∈ { 𝑥 ∣ 𝜓 } ↔ 𝐵 ∈ { 𝑦 ∣ 𝜒 } ) )
5 df-sbc ⊢ ( [ 𝐴 / 𝑥 ] 𝜓 ↔ 𝐴 ∈ { 𝑥 ∣ 𝜓 } )
6 df-sbc ⊢ ( [ 𝐵 / 𝑦 ] 𝜒 ↔ 𝐵 ∈ { 𝑦 ∣ 𝜒 } )
7 4 5 6 3bitr4g ⊢ ( 𝜑 → ( [ 𝐴 / 𝑥 ] 𝜓 ↔ [ 𝐵 / 𝑦 ] 𝜒 ) )