| Step |
Hyp |
Ref |
Expression |
| 1 |
|
vex |
⊢ 𝑥 ∈ V |
| 2 |
|
vex |
⊢ 𝑦 ∈ V |
| 3 |
1 2
|
brelrn |
⊢ ( 𝑥 𝐴 𝑦 → 𝑦 ∈ ran 𝐴 ) |
| 4 |
|
vex |
⊢ 𝑧 ∈ V |
| 5 |
4
|
brresi |
⊢ ( 𝑦 ( 𝐵 ↾ ran 𝐴 ) 𝑧 ↔ ( 𝑦 ∈ ran 𝐴 ∧ 𝑦 𝐵 𝑧 ) ) |
| 6 |
5
|
baib |
⊢ ( 𝑦 ∈ ran 𝐴 → ( 𝑦 ( 𝐵 ↾ ran 𝐴 ) 𝑧 ↔ 𝑦 𝐵 𝑧 ) ) |
| 7 |
3 6
|
syl |
⊢ ( 𝑥 𝐴 𝑦 → ( 𝑦 ( 𝐵 ↾ ran 𝐴 ) 𝑧 ↔ 𝑦 𝐵 𝑧 ) ) |
| 8 |
7
|
pm5.32i |
⊢ ( ( 𝑥 𝐴 𝑦 ∧ 𝑦 ( 𝐵 ↾ ran 𝐴 ) 𝑧 ) ↔ ( 𝑥 𝐴 𝑦 ∧ 𝑦 𝐵 𝑧 ) ) |
| 9 |
8
|
exbii |
⊢ ( ∃ 𝑦 ( 𝑥 𝐴 𝑦 ∧ 𝑦 ( 𝐵 ↾ ran 𝐴 ) 𝑧 ) ↔ ∃ 𝑦 ( 𝑥 𝐴 𝑦 ∧ 𝑦 𝐵 𝑧 ) ) |
| 10 |
9
|
opabbii |
⊢ { 〈 𝑥 , 𝑧 〉 ∣ ∃ 𝑦 ( 𝑥 𝐴 𝑦 ∧ 𝑦 ( 𝐵 ↾ ran 𝐴 ) 𝑧 ) } = { 〈 𝑥 , 𝑧 〉 ∣ ∃ 𝑦 ( 𝑥 𝐴 𝑦 ∧ 𝑦 𝐵 𝑧 ) } |
| 11 |
|
df-co |
⊢ ( ( 𝐵 ↾ ran 𝐴 ) ∘ 𝐴 ) = { 〈 𝑥 , 𝑧 〉 ∣ ∃ 𝑦 ( 𝑥 𝐴 𝑦 ∧ 𝑦 ( 𝐵 ↾ ran 𝐴 ) 𝑧 ) } |
| 12 |
|
df-co |
⊢ ( 𝐵 ∘ 𝐴 ) = { 〈 𝑥 , 𝑧 〉 ∣ ∃ 𝑦 ( 𝑥 𝐴 𝑦 ∧ 𝑦 𝐵 𝑧 ) } |
| 13 |
10 11 12
|
3eqtr4i |
⊢ ( ( 𝐵 ↾ ran 𝐴 ) ∘ 𝐴 ) = ( 𝐵 ∘ 𝐴 ) |