Metamath Proof Explorer


Theorem dfafn5b

Description: Representation of a function in terms of its values, analogous to dffn5 (only if it is assumed that the function value for each x is a set). (Contributed by Alexander van der Vekens, 25-May-2017)

Ref Expression
Assertion dfafn5b ( ∀ 𝑥𝐴 ( 𝐹 ''' 𝑥 ) ∈ 𝑉 → ( 𝐹 Fn 𝐴𝐹 = ( 𝑥𝐴 ↦ ( 𝐹 ''' 𝑥 ) ) ) )

Proof

Step Hyp Ref Expression
1 dfafn5a ( 𝐹 Fn 𝐴𝐹 = ( 𝑥𝐴 ↦ ( 𝐹 ''' 𝑥 ) ) )
2 eqid ( 𝑥𝐴 ↦ ( 𝐹 ''' 𝑥 ) ) = ( 𝑥𝐴 ↦ ( 𝐹 ''' 𝑥 ) )
3 2 fnmpt ( ∀ 𝑥𝐴 ( 𝐹 ''' 𝑥 ) ∈ 𝑉 → ( 𝑥𝐴 ↦ ( 𝐹 ''' 𝑥 ) ) Fn 𝐴 )
4 fneq1 ( 𝐹 = ( 𝑥𝐴 ↦ ( 𝐹 ''' 𝑥 ) ) → ( 𝐹 Fn 𝐴 ↔ ( 𝑥𝐴 ↦ ( 𝐹 ''' 𝑥 ) ) Fn 𝐴 ) )
5 3 4 syl5ibrcom ( ∀ 𝑥𝐴 ( 𝐹 ''' 𝑥 ) ∈ 𝑉 → ( 𝐹 = ( 𝑥𝐴 ↦ ( 𝐹 ''' 𝑥 ) ) → 𝐹 Fn 𝐴 ) )
6 1 5 impbid2 ( ∀ 𝑥𝐴 ( 𝐹 ''' 𝑥 ) ∈ 𝑉 → ( 𝐹 Fn 𝐴𝐹 = ( 𝑥𝐴 ↦ ( 𝐹 ''' 𝑥 ) ) ) )