Metamath Proof Explorer


Theorem elcnvcnvintab

Description: Two ways of saying a set is an element of the converse of the converse of the intersection of a class. (Contributed by RP, 20-Aug-2020)

Ref Expression
Assertion elcnvcnvintab ( 𝐴 ∈ ◡ ◡ ∩ { 𝑥 ∣ 𝜑 } ↔ ( 𝐴 ∈ ( V × V ) ∧ ∀ 𝑥 ( 𝜑 → 𝐴 ∈ 𝑥 ) ) )

Proof

Step Hyp Ref Expression
1 cnvcnv ⊢ ◡ ◡ ∩ { 𝑥 ∣ 𝜑 } = ( ∩ { 𝑥 ∣ 𝜑 } ∩ ( V × V ) )
2 incom ⊢ ( ∩ { 𝑥 ∣ 𝜑 } ∩ ( V × V ) ) = ( ( V × V ) ∩ ∩ { 𝑥 ∣ 𝜑 } )
3 1 2 eqtri ⊢ ◡ ◡ ∩ { 𝑥 ∣ 𝜑 } = ( ( V × V ) ∩ ∩ { 𝑥 ∣ 𝜑 } )
4 3 eleq2i ⊢ ( 𝐴 ∈ ◡ ◡ ∩ { 𝑥 ∣ 𝜑 } ↔ 𝐴 ∈ ( ( V × V ) ∩ ∩ { 𝑥 ∣ 𝜑 } ) )
5 elinintab ⊢ ( 𝐴 ∈ ( ( V × V ) ∩ ∩ { 𝑥 ∣ 𝜑 } ) ↔ ( 𝐴 ∈ ( V × V ) ∧ ∀ 𝑥 ( 𝜑 → 𝐴 ∈ 𝑥 ) ) )
6 4 5 bitri ⊢ ( 𝐴 ∈ ◡ ◡ ∩ { 𝑥 ∣ 𝜑 } ↔ ( 𝐴 ∈ ( V × V ) ∧ ∀ 𝑥 ( 𝜑 → 𝐴 ∈ 𝑥 ) ) )