Metamath Proof Explorer


Theorem elcnvcnvintab

Description: Two ways of saying a set is an element of the converse of the converse of the intersection of a class. (Contributed by RP, 20-Aug-2020)

Ref Expression
Assertion elcnvcnvintab ⊢ A ∈ ⋂ x | φ -1 -1 ↔ A ∈ V × V ∧ ∀ x φ → A ∈ x

Proof

Step Hyp Ref Expression
1 cnvcnv ⊢ ⋂ x | φ -1 -1 = ⋂ x | φ ∩ V × V
2 incom ⊢ ⋂ x | φ ∩ V × V = V × V ∩ ⋂ x | φ
3 1 2 eqtri ⊢ ⋂ x | φ -1 -1 = V × V ∩ ⋂ x | φ
4 3 eleq2i ⊢ A ∈ ⋂ x | φ -1 -1 ↔ A ∈ V × V ∩ ⋂ x | φ
5 elinintab ⊢ A ∈ V × V ∩ ⋂ x | φ ↔ A ∈ V × V ∧ ∀ x φ → A ∈ x
6 4 5 bitri ⊢ A ∈ ⋂ x | φ -1 -1 ↔ A ∈ V × V ∧ ∀ x φ → A ∈ x