Metamath Proof Explorer


Theorem elprneb

Description: An element of a proper unordered pair is the first element iff it is not the second element. (Contributed by AV, 18-Jun-2020)

Ref Expression
Assertion elprneb ( ( 𝐴 ∈ { 𝐵 , 𝐶 } ∧ 𝐵 ≠ 𝐶 ) → ( 𝐴 = 𝐵 ↔ 𝐴 ≠ 𝐶 ) )

Proof

Step Hyp Ref Expression
1 elpri ⊢ ( 𝐴 ∈ { 𝐵 , 𝐶 } → ( 𝐴 = 𝐵 ∨ 𝐴 = 𝐶 ) )
2 neeq1 ⊢ ( 𝐵 = 𝐴 → ( 𝐵 ≠ 𝐶 ↔ 𝐴 ≠ 𝐶 ) )
3 2 eqcoms ⊢ ( 𝐴 = 𝐵 → ( 𝐵 ≠ 𝐶 ↔ 𝐴 ≠ 𝐶 ) )
4 pm5.1 ⊢ ( ( 𝐴 = 𝐵 ∧ 𝐴 ≠ 𝐶 ) → ( 𝐴 = 𝐵 ↔ 𝐴 ≠ 𝐶 ) )
5 4 ex ⊢ ( 𝐴 = 𝐵 → ( 𝐴 ≠ 𝐶 → ( 𝐴 = 𝐵 ↔ 𝐴 ≠ 𝐶 ) ) )
6 3 5 sylbid ⊢ ( 𝐴 = 𝐵 → ( 𝐵 ≠ 𝐶 → ( 𝐴 = 𝐵 ↔ 𝐴 ≠ 𝐶 ) ) )
7 neeq2 ⊢ ( 𝐴 = 𝐶 → ( 𝐵 ≠ 𝐴 ↔ 𝐵 ≠ 𝐶 ) )
8 nesym ⊢ ( 𝐵 ≠ 𝐴 ↔ ¬ 𝐴 = 𝐵 )
9 pm5.1 ⊢ ( ( 𝐴 = 𝐶 ∧ ¬ 𝐴 = 𝐵 ) → ( 𝐴 = 𝐶 ↔ ¬ 𝐴 = 𝐵 ) )
10 8 9 sylan2b ⊢ ( ( 𝐴 = 𝐶 ∧ 𝐵 ≠ 𝐴 ) → ( 𝐴 = 𝐶 ↔ ¬ 𝐴 = 𝐵 ) )
11 10 necon2abid ⊢ ( ( 𝐴 = 𝐶 ∧ 𝐵 ≠ 𝐴 ) → ( 𝐴 = 𝐵 ↔ 𝐴 ≠ 𝐶 ) )
12 11 ex ⊢ ( 𝐴 = 𝐶 → ( 𝐵 ≠ 𝐴 → ( 𝐴 = 𝐵 ↔ 𝐴 ≠ 𝐶 ) ) )
13 7 12 sylbird ⊢ ( 𝐴 = 𝐶 → ( 𝐵 ≠ 𝐶 → ( 𝐴 = 𝐵 ↔ 𝐴 ≠ 𝐶 ) ) )
14 6 13 jaoi ⊢ ( ( 𝐴 = 𝐵 ∨ 𝐴 = 𝐶 ) → ( 𝐵 ≠ 𝐶 → ( 𝐴 = 𝐵 ↔ 𝐴 ≠ 𝐶 ) ) )
15 1 14 syl ⊢ ( 𝐴 ∈ { 𝐵 , 𝐶 } → ( 𝐵 ≠ 𝐶 → ( 𝐴 = 𝐵 ↔ 𝐴 ≠ 𝐶 ) ) )
16 15 imp ⊢ ( ( 𝐴 ∈ { 𝐵 , 𝐶 } ∧ 𝐵 ≠ 𝐶 ) → ( 𝐴 = 𝐵 ↔ 𝐴 ≠ 𝐶 ) )