Metamath Proof Explorer


Theorem fldextress

Description: Field extension implies a structure restriction relation. (Contributed by Thierry Arnoux, 29-Jul-2023)

Ref Expression
Assertion fldextress ( 𝐸 /FldExt 𝐹𝐹 = ( 𝐸s ( Base ‘ 𝐹 ) ) )

Proof

Step Hyp Ref Expression
1 fldextfld1 ( 𝐸 /FldExt 𝐹𝐸 ∈ Field )
2 fldextfld2 ( 𝐸 /FldExt 𝐹𝐹 ∈ Field )
3 brfldext ( ( 𝐸 ∈ Field ∧ 𝐹 ∈ Field ) → ( 𝐸 /FldExt 𝐹 ↔ ( 𝐹 = ( 𝐸s ( Base ‘ 𝐹 ) ) ∧ ( Base ‘ 𝐹 ) ∈ ( SubRing ‘ 𝐸 ) ) ) )
4 1 2 3 syl2anc ( 𝐸 /FldExt 𝐹 → ( 𝐸 /FldExt 𝐹 ↔ ( 𝐹 = ( 𝐸s ( Base ‘ 𝐹 ) ) ∧ ( Base ‘ 𝐹 ) ∈ ( SubRing ‘ 𝐸 ) ) ) )
5 4 ibi ( 𝐸 /FldExt 𝐹 → ( 𝐹 = ( 𝐸s ( Base ‘ 𝐹 ) ) ∧ ( Base ‘ 𝐹 ) ∈ ( SubRing ‘ 𝐸 ) ) )
6 5 simpld ( 𝐸 /FldExt 𝐹𝐹 = ( 𝐸s ( Base ‘ 𝐹 ) ) )