Metamath Proof Explorer


Theorem fniniseg2

Description: Inverse point images under functions expressed as abstractions. (Contributed by Stefan O'Rear, 1-Feb-2015)

Ref Expression
Assertion fniniseg2 ( 𝐹 Fn 𝐴 → ( ◡ 𝐹 “ { 𝐵 } ) = { 𝑥 ∈ 𝐴 ∣ ( 𝐹 ‘ 𝑥 ) = 𝐵 } )

Proof

Step Hyp Ref Expression
1 fncnvima2 ⊢ ( 𝐹 Fn 𝐴 → ( ◡ 𝐹 “ { 𝐵 } ) = { 𝑥 ∈ 𝐴 ∣ ( 𝐹 ‘ 𝑥 ) ∈ { 𝐵 } } )
2 fvex ⊢ ( 𝐹 ‘ 𝑥 ) ∈ V
3 2 elsn ⊢ ( ( 𝐹 ‘ 𝑥 ) ∈ { 𝐵 } ↔ ( 𝐹 ‘ 𝑥 ) = 𝐵 )
4 3 rabbii ⊢ { 𝑥 ∈ 𝐴 ∣ ( 𝐹 ‘ 𝑥 ) ∈ { 𝐵 } } = { 𝑥 ∈ 𝐴 ∣ ( 𝐹 ‘ 𝑥 ) = 𝐵 }
5 1 4 eqtrdi ⊢ ( 𝐹 Fn 𝐴 → ( ◡ 𝐹 “ { 𝐵 } ) = { 𝑥 ∈ 𝐴 ∣ ( 𝐹 ‘ 𝑥 ) = 𝐵 } )