Metamath Proof Explorer


Theorem frecseq123

Description: Equality theorem for founded recursion generator. (Contributed by Scott Fenton, 23-Dec-2021)

Ref Expression
Assertion frecseq123 ( ( 𝑅 = 𝑆𝐴 = 𝐵𝐹 = 𝐺 ) → frecs ( 𝑅 , 𝐴 , 𝐹 ) = frecs ( 𝑆 , 𝐵 , 𝐺 ) )

Proof

Step Hyp Ref Expression
1 simp2 ( ( 𝑅 = 𝑆𝐴 = 𝐵𝐹 = 𝐺 ) → 𝐴 = 𝐵 )
2 1 sseq2d ( ( 𝑅 = 𝑆𝐴 = 𝐵𝐹 = 𝐺 ) → ( 𝑥𝐴𝑥𝐵 ) )
3 equid 𝑦 = 𝑦
4 predeq123 ( ( 𝑅 = 𝑆𝐴 = 𝐵𝑦 = 𝑦 ) → Pred ( 𝑅 , 𝐴 , 𝑦 ) = Pred ( 𝑆 , 𝐵 , 𝑦 ) )
5 3 4 mp3an3 ( ( 𝑅 = 𝑆𝐴 = 𝐵 ) → Pred ( 𝑅 , 𝐴 , 𝑦 ) = Pred ( 𝑆 , 𝐵 , 𝑦 ) )
6 5 3adant3 ( ( 𝑅 = 𝑆𝐴 = 𝐵𝐹 = 𝐺 ) → Pred ( 𝑅 , 𝐴 , 𝑦 ) = Pred ( 𝑆 , 𝐵 , 𝑦 ) )
7 6 sseq1d ( ( 𝑅 = 𝑆𝐴 = 𝐵𝐹 = 𝐺 ) → ( Pred ( 𝑅 , 𝐴 , 𝑦 ) ⊆ 𝑥 ↔ Pred ( 𝑆 , 𝐵 , 𝑦 ) ⊆ 𝑥 ) )
8 7 ralbidv ( ( 𝑅 = 𝑆𝐴 = 𝐵𝐹 = 𝐺 ) → ( ∀ 𝑦𝑥 Pred ( 𝑅 , 𝐴 , 𝑦 ) ⊆ 𝑥 ↔ ∀ 𝑦𝑥 Pred ( 𝑆 , 𝐵 , 𝑦 ) ⊆ 𝑥 ) )
9 2 8 anbi12d ( ( 𝑅 = 𝑆𝐴 = 𝐵𝐹 = 𝐺 ) → ( ( 𝑥𝐴 ∧ ∀ 𝑦𝑥 Pred ( 𝑅 , 𝐴 , 𝑦 ) ⊆ 𝑥 ) ↔ ( 𝑥𝐵 ∧ ∀ 𝑦𝑥 Pred ( 𝑆 , 𝐵 , 𝑦 ) ⊆ 𝑥 ) ) )
10 simp3 ( ( 𝑅 = 𝑆𝐴 = 𝐵𝐹 = 𝐺 ) → 𝐹 = 𝐺 )
11 10 oveqd ( ( 𝑅 = 𝑆𝐴 = 𝐵𝐹 = 𝐺 ) → ( 𝑦 𝐹 ( 𝑓 ↾ Pred ( 𝑅 , 𝐴 , 𝑦 ) ) ) = ( 𝑦 𝐺 ( 𝑓 ↾ Pred ( 𝑅 , 𝐴 , 𝑦 ) ) ) )
12 6 reseq2d ( ( 𝑅 = 𝑆𝐴 = 𝐵𝐹 = 𝐺 ) → ( 𝑓 ↾ Pred ( 𝑅 , 𝐴 , 𝑦 ) ) = ( 𝑓 ↾ Pred ( 𝑆 , 𝐵 , 𝑦 ) ) )
13 12 oveq2d ( ( 𝑅 = 𝑆𝐴 = 𝐵𝐹 = 𝐺 ) → ( 𝑦 𝐺 ( 𝑓 ↾ Pred ( 𝑅 , 𝐴 , 𝑦 ) ) ) = ( 𝑦 𝐺 ( 𝑓 ↾ Pred ( 𝑆 , 𝐵 , 𝑦 ) ) ) )
14 11 13 eqtrd ( ( 𝑅 = 𝑆𝐴 = 𝐵𝐹 = 𝐺 ) → ( 𝑦 𝐹 ( 𝑓 ↾ Pred ( 𝑅 , 𝐴 , 𝑦 ) ) ) = ( 𝑦 𝐺 ( 𝑓 ↾ Pred ( 𝑆 , 𝐵 , 𝑦 ) ) ) )
15 14 eqeq2d ( ( 𝑅 = 𝑆𝐴 = 𝐵𝐹 = 𝐺 ) → ( ( 𝑓𝑦 ) = ( 𝑦 𝐹 ( 𝑓 ↾ Pred ( 𝑅 , 𝐴 , 𝑦 ) ) ) ↔ ( 𝑓𝑦 ) = ( 𝑦 𝐺 ( 𝑓 ↾ Pred ( 𝑆 , 𝐵 , 𝑦 ) ) ) ) )
16 15 ralbidv ( ( 𝑅 = 𝑆𝐴 = 𝐵𝐹 = 𝐺 ) → ( ∀ 𝑦𝑥 ( 𝑓𝑦 ) = ( 𝑦 𝐹 ( 𝑓 ↾ Pred ( 𝑅 , 𝐴 , 𝑦 ) ) ) ↔ ∀ 𝑦𝑥 ( 𝑓𝑦 ) = ( 𝑦 𝐺 ( 𝑓 ↾ Pred ( 𝑆 , 𝐵 , 𝑦 ) ) ) ) )
17 9 16 3anbi23d ( ( 𝑅 = 𝑆𝐴 = 𝐵𝐹 = 𝐺 ) → ( ( 𝑓 Fn 𝑥 ∧ ( 𝑥𝐴 ∧ ∀ 𝑦𝑥 Pred ( 𝑅 , 𝐴 , 𝑦 ) ⊆ 𝑥 ) ∧ ∀ 𝑦𝑥 ( 𝑓𝑦 ) = ( 𝑦 𝐹 ( 𝑓 ↾ Pred ( 𝑅 , 𝐴 , 𝑦 ) ) ) ) ↔ ( 𝑓 Fn 𝑥 ∧ ( 𝑥𝐵 ∧ ∀ 𝑦𝑥 Pred ( 𝑆 , 𝐵 , 𝑦 ) ⊆ 𝑥 ) ∧ ∀ 𝑦𝑥 ( 𝑓𝑦 ) = ( 𝑦 𝐺 ( 𝑓 ↾ Pred ( 𝑆 , 𝐵 , 𝑦 ) ) ) ) ) )
18 17 exbidv ( ( 𝑅 = 𝑆𝐴 = 𝐵𝐹 = 𝐺 ) → ( ∃ 𝑥 ( 𝑓 Fn 𝑥 ∧ ( 𝑥𝐴 ∧ ∀ 𝑦𝑥 Pred ( 𝑅 , 𝐴 , 𝑦 ) ⊆ 𝑥 ) ∧ ∀ 𝑦𝑥 ( 𝑓𝑦 ) = ( 𝑦 𝐹 ( 𝑓 ↾ Pred ( 𝑅 , 𝐴 , 𝑦 ) ) ) ) ↔ ∃ 𝑥 ( 𝑓 Fn 𝑥 ∧ ( 𝑥𝐵 ∧ ∀ 𝑦𝑥 Pred ( 𝑆 , 𝐵 , 𝑦 ) ⊆ 𝑥 ) ∧ ∀ 𝑦𝑥 ( 𝑓𝑦 ) = ( 𝑦 𝐺 ( 𝑓 ↾ Pred ( 𝑆 , 𝐵 , 𝑦 ) ) ) ) ) )
19 18 abbidv ( ( 𝑅 = 𝑆𝐴 = 𝐵𝐹 = 𝐺 ) → { 𝑓 ∣ ∃ 𝑥 ( 𝑓 Fn 𝑥 ∧ ( 𝑥𝐴 ∧ ∀ 𝑦𝑥 Pred ( 𝑅 , 𝐴 , 𝑦 ) ⊆ 𝑥 ) ∧ ∀ 𝑦𝑥 ( 𝑓𝑦 ) = ( 𝑦 𝐹 ( 𝑓 ↾ Pred ( 𝑅 , 𝐴 , 𝑦 ) ) ) ) } = { 𝑓 ∣ ∃ 𝑥 ( 𝑓 Fn 𝑥 ∧ ( 𝑥𝐵 ∧ ∀ 𝑦𝑥 Pred ( 𝑆 , 𝐵 , 𝑦 ) ⊆ 𝑥 ) ∧ ∀ 𝑦𝑥 ( 𝑓𝑦 ) = ( 𝑦 𝐺 ( 𝑓 ↾ Pred ( 𝑆 , 𝐵 , 𝑦 ) ) ) ) } )
20 19 unieqd ( ( 𝑅 = 𝑆𝐴 = 𝐵𝐹 = 𝐺 ) → { 𝑓 ∣ ∃ 𝑥 ( 𝑓 Fn 𝑥 ∧ ( 𝑥𝐴 ∧ ∀ 𝑦𝑥 Pred ( 𝑅 , 𝐴 , 𝑦 ) ⊆ 𝑥 ) ∧ ∀ 𝑦𝑥 ( 𝑓𝑦 ) = ( 𝑦 𝐹 ( 𝑓 ↾ Pred ( 𝑅 , 𝐴 , 𝑦 ) ) ) ) } = { 𝑓 ∣ ∃ 𝑥 ( 𝑓 Fn 𝑥 ∧ ( 𝑥𝐵 ∧ ∀ 𝑦𝑥 Pred ( 𝑆 , 𝐵 , 𝑦 ) ⊆ 𝑥 ) ∧ ∀ 𝑦𝑥 ( 𝑓𝑦 ) = ( 𝑦 𝐺 ( 𝑓 ↾ Pred ( 𝑆 , 𝐵 , 𝑦 ) ) ) ) } )
21 df-frecs frecs ( 𝑅 , 𝐴 , 𝐹 ) = { 𝑓 ∣ ∃ 𝑥 ( 𝑓 Fn 𝑥 ∧ ( 𝑥𝐴 ∧ ∀ 𝑦𝑥 Pred ( 𝑅 , 𝐴 , 𝑦 ) ⊆ 𝑥 ) ∧ ∀ 𝑦𝑥 ( 𝑓𝑦 ) = ( 𝑦 𝐹 ( 𝑓 ↾ Pred ( 𝑅 , 𝐴 , 𝑦 ) ) ) ) }
22 df-frecs frecs ( 𝑆 , 𝐵 , 𝐺 ) = { 𝑓 ∣ ∃ 𝑥 ( 𝑓 Fn 𝑥 ∧ ( 𝑥𝐵 ∧ ∀ 𝑦𝑥 Pred ( 𝑆 , 𝐵 , 𝑦 ) ⊆ 𝑥 ) ∧ ∀ 𝑦𝑥 ( 𝑓𝑦 ) = ( 𝑦 𝐺 ( 𝑓 ↾ Pred ( 𝑆 , 𝐵 , 𝑦 ) ) ) ) }
23 20 21 22 3eqtr4g ( ( 𝑅 = 𝑆𝐴 = 𝐵𝐹 = 𝐺 ) → frecs ( 𝑅 , 𝐴 , 𝐹 ) = frecs ( 𝑆 , 𝐵 , 𝐺 ) )