Metamath Proof Explorer


Theorem linindscl

Description: A linearly independent set is a subset of (the base set of) a module. (Contributed by AV, 13-Apr-2019)

Ref Expression
Assertion linindscl ( 𝑆 linIndS 𝑀 → 𝑆 ∈ 𝒫 ( Base ‘ 𝑀 ) )

Proof

Step Hyp Ref Expression
1 eqid ⊢ ( Base ‘ 𝑀 ) = ( Base ‘ 𝑀 )
2 eqid ⊢ ( 0g ‘ 𝑀 ) = ( 0g ‘ 𝑀 )
3 eqid ⊢ ( Scalar ‘ 𝑀 ) = ( Scalar ‘ 𝑀 )
4 eqid ⊢ ( Base ‘ ( Scalar ‘ 𝑀 ) ) = ( Base ‘ ( Scalar ‘ 𝑀 ) )
5 eqid ⊢ ( 0g ‘ ( Scalar ‘ 𝑀 ) ) = ( 0g ‘ ( Scalar ‘ 𝑀 ) )
6 1 2 3 4 5 linindsi ⊢ ( 𝑆 linIndS 𝑀 → ( 𝑆 ∈ 𝒫 ( Base ‘ 𝑀 ) ∧ ∀ 𝑓 ∈ ( ( Base ‘ ( Scalar ‘ 𝑀 ) ) ↑m 𝑆 ) ( ( 𝑓 finSupp ( 0g ‘ ( Scalar ‘ 𝑀 ) ) ∧ ( 𝑓 ( linC ‘ 𝑀 ) 𝑆 ) = ( 0g ‘ 𝑀 ) ) → ∀ 𝑥 ∈ 𝑆 ( 𝑓 ‘ 𝑥 ) = ( 0g ‘ ( Scalar ‘ 𝑀 ) ) ) ) )
7 6 simpld ⊢ ( 𝑆 linIndS 𝑀 → 𝑆 ∈ 𝒫 ( Base ‘ 𝑀 ) )