Metamath Proof Explorer


Theorem mapdvalc

Description: Value of projectivity from vector space H to dual space. (Contributed by NM, 27-Jan-2015)

Ref Expression
Hypotheses mapdval.h ⊢ 𝐻 = ( LHyp ‘ 𝐾 )
mapdval.u ⊢ 𝑈 = ( ( DVecH ‘ 𝐾 ) ‘ 𝑊 )
mapdval.s ⊢ 𝑆 = ( LSubSp ‘ 𝑈 )
mapdval.f ⊢ 𝐹 = ( LFnl ‘ 𝑈 )
mapdval.l ⊢ 𝐿 = ( LKer ‘ 𝑈 )
mapdval.o ⊢ 𝑂 = ( ( ocH ‘ 𝐾 ) ‘ 𝑊 )
mapdval.m ⊢ 𝑀 = ( ( mapd ‘ 𝐾 ) ‘ 𝑊 )
mapdval.k ⊢ ( 𝜑 → ( 𝐾 ∈ 𝑋 ∧ 𝑊 ∈ 𝐻 ) )
mapdval.t ⊢ ( 𝜑 → 𝑇 ∈ 𝑆 )
mapdvalc.c ⊢ 𝐶 = { 𝑔 ∈ 𝐹 ∣ ( 𝑂 ‘ ( 𝑂 ‘ ( 𝐿 ‘ 𝑔 ) ) ) = ( 𝐿 ‘ 𝑔 ) }
Assertion mapdvalc ( 𝜑 → ( 𝑀 ‘ 𝑇 ) = { 𝑓 ∈ 𝐶 ∣ ( 𝑂 ‘ ( 𝐿 ‘ 𝑓 ) ) ⊆ 𝑇 } )

Proof

Step Hyp Ref Expression
1 mapdval.h ⊢ 𝐻 = ( LHyp ‘ 𝐾 )
2 mapdval.u ⊢ 𝑈 = ( ( DVecH ‘ 𝐾 ) ‘ 𝑊 )
3 mapdval.s ⊢ 𝑆 = ( LSubSp ‘ 𝑈 )
4 mapdval.f ⊢ 𝐹 = ( LFnl ‘ 𝑈 )
5 mapdval.l ⊢ 𝐿 = ( LKer ‘ 𝑈 )
6 mapdval.o ⊢ 𝑂 = ( ( ocH ‘ 𝐾 ) ‘ 𝑊 )
7 mapdval.m ⊢ 𝑀 = ( ( mapd ‘ 𝐾 ) ‘ 𝑊 )
8 mapdval.k ⊢ ( 𝜑 → ( 𝐾 ∈ 𝑋 ∧ 𝑊 ∈ 𝐻 ) )
9 mapdval.t ⊢ ( 𝜑 → 𝑇 ∈ 𝑆 )
10 mapdvalc.c ⊢ 𝐶 = { 𝑔 ∈ 𝐹 ∣ ( 𝑂 ‘ ( 𝑂 ‘ ( 𝐿 ‘ 𝑔 ) ) ) = ( 𝐿 ‘ 𝑔 ) }
11 1 2 3 4 5 6 7 8 9 mapdval ⊢ ( 𝜑 → ( 𝑀 ‘ 𝑇 ) = { 𝑓 ∈ 𝐹 ∣ ( ( 𝑂 ‘ ( 𝑂 ‘ ( 𝐿 ‘ 𝑓 ) ) ) = ( 𝐿 ‘ 𝑓 ) ∧ ( 𝑂 ‘ ( 𝐿 ‘ 𝑓 ) ) ⊆ 𝑇 ) } )
12 anass ⊢ ( ( ( 𝑓 ∈ 𝐹 ∧ ( 𝑂 ‘ ( 𝑂 ‘ ( 𝐿 ‘ 𝑓 ) ) ) = ( 𝐿 ‘ 𝑓 ) ) ∧ ( 𝑂 ‘ ( 𝐿 ‘ 𝑓 ) ) ⊆ 𝑇 ) ↔ ( 𝑓 ∈ 𝐹 ∧ ( ( 𝑂 ‘ ( 𝑂 ‘ ( 𝐿 ‘ 𝑓 ) ) ) = ( 𝐿 ‘ 𝑓 ) ∧ ( 𝑂 ‘ ( 𝐿 ‘ 𝑓 ) ) ⊆ 𝑇 ) ) )
13 10 lcfl1lem ⊢ ( 𝑓 ∈ 𝐶 ↔ ( 𝑓 ∈ 𝐹 ∧ ( 𝑂 ‘ ( 𝑂 ‘ ( 𝐿 ‘ 𝑓 ) ) ) = ( 𝐿 ‘ 𝑓 ) ) )
14 13 anbi1i ⊢ ( ( 𝑓 ∈ 𝐶 ∧ ( 𝑂 ‘ ( 𝐿 ‘ 𝑓 ) ) ⊆ 𝑇 ) ↔ ( ( 𝑓 ∈ 𝐹 ∧ ( 𝑂 ‘ ( 𝑂 ‘ ( 𝐿 ‘ 𝑓 ) ) ) = ( 𝐿 ‘ 𝑓 ) ) ∧ ( 𝑂 ‘ ( 𝐿 ‘ 𝑓 ) ) ⊆ 𝑇 ) )
15 14 bicomi ⊢ ( ( ( 𝑓 ∈ 𝐹 ∧ ( 𝑂 ‘ ( 𝑂 ‘ ( 𝐿 ‘ 𝑓 ) ) ) = ( 𝐿 ‘ 𝑓 ) ) ∧ ( 𝑂 ‘ ( 𝐿 ‘ 𝑓 ) ) ⊆ 𝑇 ) ↔ ( 𝑓 ∈ 𝐶 ∧ ( 𝑂 ‘ ( 𝐿 ‘ 𝑓 ) ) ⊆ 𝑇 ) )
16 15 a1i ⊢ ( 𝜑 → ( ( ( 𝑓 ∈ 𝐹 ∧ ( 𝑂 ‘ ( 𝑂 ‘ ( 𝐿 ‘ 𝑓 ) ) ) = ( 𝐿 ‘ 𝑓 ) ) ∧ ( 𝑂 ‘ ( 𝐿 ‘ 𝑓 ) ) ⊆ 𝑇 ) ↔ ( 𝑓 ∈ 𝐶 ∧ ( 𝑂 ‘ ( 𝐿 ‘ 𝑓 ) ) ⊆ 𝑇 ) ) )
17 12 16 bitr3id ⊢ ( 𝜑 → ( ( 𝑓 ∈ 𝐹 ∧ ( ( 𝑂 ‘ ( 𝑂 ‘ ( 𝐿 ‘ 𝑓 ) ) ) = ( 𝐿 ‘ 𝑓 ) ∧ ( 𝑂 ‘ ( 𝐿 ‘ 𝑓 ) ) ⊆ 𝑇 ) ) ↔ ( 𝑓 ∈ 𝐶 ∧ ( 𝑂 ‘ ( 𝐿 ‘ 𝑓 ) ) ⊆ 𝑇 ) ) )
18 17 rabbidva2 ⊢ ( 𝜑 → { 𝑓 ∈ 𝐹 ∣ ( ( 𝑂 ‘ ( 𝑂 ‘ ( 𝐿 ‘ 𝑓 ) ) ) = ( 𝐿 ‘ 𝑓 ) ∧ ( 𝑂 ‘ ( 𝐿 ‘ 𝑓 ) ) ⊆ 𝑇 ) } = { 𝑓 ∈ 𝐶 ∣ ( 𝑂 ‘ ( 𝐿 ‘ 𝑓 ) ) ⊆ 𝑇 } )
19 11 18 eqtrd ⊢ ( 𝜑 → ( 𝑀 ‘ 𝑇 ) = { 𝑓 ∈ 𝐶 ∣ ( 𝑂 ‘ ( 𝐿 ‘ 𝑓 ) ) ⊆ 𝑇 } )