Metamath Proof Explorer


Theorem mvrrsubd

Description: Move a subtraction in the RHS to a right-addition in the LHS. Converse of mvlraddd . (Contributed by SN, 21-Aug-2024)

Ref Expression
Hypotheses mvrrsubd.a ⊢ ( 𝜑 → 𝐵 ∈ ℂ )
mvrrsubd.b ⊢ ( 𝜑 → 𝐶 ∈ ℂ )
mvrrsubd.1 ⊢ ( 𝜑 → 𝐴 = ( 𝐵 − 𝐶 ) )
Assertion mvrrsubd ( 𝜑 → ( 𝐴 + 𝐶 ) = 𝐵 )

Proof

Step Hyp Ref Expression
1 mvrrsubd.a ⊢ ( 𝜑 → 𝐵 ∈ ℂ )
2 mvrrsubd.b ⊢ ( 𝜑 → 𝐶 ∈ ℂ )
3 mvrrsubd.1 ⊢ ( 𝜑 → 𝐴 = ( 𝐵 − 𝐶 ) )
4 1 2 subcld ⊢ ( 𝜑 → ( 𝐵 − 𝐶 ) ∈ ℂ )
5 3 4 eqeltrd ⊢ ( 𝜑 → 𝐴 ∈ ℂ )
6 5 2 addcld ⊢ ( 𝜑 → ( 𝐴 + 𝐶 ) ∈ ℂ )
7 5 2 pncand ⊢ ( 𝜑 → ( ( 𝐴 + 𝐶 ) − 𝐶 ) = 𝐴 )
8 7 3 eqtrd ⊢ ( 𝜑 → ( ( 𝐴 + 𝐶 ) − 𝐶 ) = ( 𝐵 − 𝐶 ) )
9 6 1 2 8 subcan2d ⊢ ( 𝜑 → ( 𝐴 + 𝐶 ) = 𝐵 )