Metamath Proof Explorer


Theorem n0abso

Description: Nonemptiness is absolute for transitive models. Compare Example I.16.3 of Kunen2 p. 96 and the following discussion. (Contributed by Eric Schmidt, 19-Oct-2025)

Ref Expression
Assertion n0abso ( ( Tr 𝑀 ∧ 𝐴 ∈ 𝑀 ) → ( 𝐴 ≠ ∅ ↔ ∃ 𝑥 ∈ 𝑀 𝑥 ∈ 𝐴 ) )

Proof

Step Hyp Ref Expression
1 rexabso ⊢ ( ( Tr 𝑀 ∧ 𝐴 ∈ 𝑀 ) → ( ∃ 𝑥 ∈ 𝐴 ⊤ ↔ ∃ 𝑥 ∈ 𝑀 ( 𝑥 ∈ 𝐴 ∧ ⊤ ) ) )
2 tru ⊢ ⊤
3 2 rext0 ⊢ ( ∃ 𝑥 ∈ 𝐴 ⊤ ↔ 𝐴 ≠ ∅ )
4 3 bicomi ⊢ ( 𝐴 ≠ ∅ ↔ ∃ 𝑥 ∈ 𝐴 ⊤ )
5 2 biantru ⊢ ( 𝑥 ∈ 𝐴 ↔ ( 𝑥 ∈ 𝐴 ∧ ⊤ ) )
6 5 rexbii ⊢ ( ∃ 𝑥 ∈ 𝑀 𝑥 ∈ 𝐴 ↔ ∃ 𝑥 ∈ 𝑀 ( 𝑥 ∈ 𝐴 ∧ ⊤ ) )
7 1 4 6 3bitr4g ⊢ ( ( Tr 𝑀 ∧ 𝐴 ∈ 𝑀 ) → ( 𝐴 ≠ ∅ ↔ ∃ 𝑥 ∈ 𝑀 𝑥 ∈ 𝐴 ) )