Metamath Proof Explorer


Theorem nodenselem7

Description: Lemma for nodense . A and B are equal at all elements of the abstraction. (Contributed by Scott Fenton, 17-Jun-2011)

Ref Expression
Assertion nodenselem7 ( ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ) ∧ ( ( bday ‘ 𝐴 ) = ( bday ‘ 𝐵 ) ∧ 𝐴 <s 𝐵 ) ) → ( 𝐶 ∈ ∩ { 𝑎 ∈ On ∣ ( 𝐴 ‘ 𝑎 ) ≠ ( 𝐵 ‘ 𝑎 ) } → ( 𝐴 ‘ 𝐶 ) = ( 𝐵 ‘ 𝐶 ) ) )

Proof

Step Hyp Ref Expression
1 simpll ⊢ ( ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ) ∧ ( ( bday ‘ 𝐴 ) = ( bday ‘ 𝐵 ) ∧ 𝐴 <s 𝐵 ) ) → 𝐴 ∈ No )
2 simplr ⊢ ( ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ) ∧ ( ( bday ‘ 𝐴 ) = ( bday ‘ 𝐵 ) ∧ 𝐴 <s 𝐵 ) ) → 𝐵 ∈ No )
3 ltsso ⊢ <s Or No
4 sonr ⊢ ( ( <s Or No ∧ 𝐴 ∈ No ) → ¬ 𝐴 <s 𝐴 )
5 3 4 mpan ⊢ ( 𝐴 ∈ No → ¬ 𝐴 <s 𝐴 )
6 breq2 ⊢ ( 𝐴 = 𝐵 → ( 𝐴 <s 𝐴 ↔ 𝐴 <s 𝐵 ) )
7 6 notbid ⊢ ( 𝐴 = 𝐵 → ( ¬ 𝐴 <s 𝐴 ↔ ¬ 𝐴 <s 𝐵 ) )
8 5 7 syl5ibcom ⊢ ( 𝐴 ∈ No → ( 𝐴 = 𝐵 → ¬ 𝐴 <s 𝐵 ) )
9 8 necon2ad ⊢ ( 𝐴 ∈ No → ( 𝐴 <s 𝐵 → 𝐴 ≠ 𝐵 ) )
10 9 imp ⊢ ( ( 𝐴 ∈ No ∧ 𝐴 <s 𝐵 ) → 𝐴 ≠ 𝐵 )
11 10 ad2ant2rl ⊢ ( ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ) ∧ ( ( bday ‘ 𝐴 ) = ( bday ‘ 𝐵 ) ∧ 𝐴 <s 𝐵 ) ) → 𝐴 ≠ 𝐵 )
12 1 2 11 3jca ⊢ ( ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ) ∧ ( ( bday ‘ 𝐴 ) = ( bday ‘ 𝐵 ) ∧ 𝐴 <s 𝐵 ) ) → ( 𝐴 ∈ No ∧ 𝐵 ∈ No ∧ 𝐴 ≠ 𝐵 ) )
13 nosepeq ⊢ ( ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ∧ 𝐴 ≠ 𝐵 ) ∧ 𝐶 ∈ ∩ { 𝑎 ∈ On ∣ ( 𝐴 ‘ 𝑎 ) ≠ ( 𝐵 ‘ 𝑎 ) } ) → ( 𝐴 ‘ 𝐶 ) = ( 𝐵 ‘ 𝐶 ) )
14 12 13 sylan ⊢ ( ( ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ) ∧ ( ( bday ‘ 𝐴 ) = ( bday ‘ 𝐵 ) ∧ 𝐴 <s 𝐵 ) ) ∧ 𝐶 ∈ ∩ { 𝑎 ∈ On ∣ ( 𝐴 ‘ 𝑎 ) ≠ ( 𝐵 ‘ 𝑎 ) } ) → ( 𝐴 ‘ 𝐶 ) = ( 𝐵 ‘ 𝐶 ) )
15 14 ex ⊢ ( ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ) ∧ ( ( bday ‘ 𝐴 ) = ( bday ‘ 𝐵 ) ∧ 𝐴 <s 𝐵 ) ) → ( 𝐶 ∈ ∩ { 𝑎 ∈ On ∣ ( 𝐴 ‘ 𝑎 ) ≠ ( 𝐵 ‘ 𝑎 ) } → ( 𝐴 ‘ 𝐶 ) = ( 𝐵 ‘ 𝐶 ) ) )