Metamath Proof Explorer


Theorem omun

Description: The union of two finite ordinals is a finite ordinal. (Contributed by Scott Fenton, 15-Mar-2025)

Ref Expression
Assertion omun ( ( 𝐴 ∈ ω ∧ 𝐵 ∈ ω ) → ( 𝐴 ∪ 𝐵 ) ∈ ω )

Proof

Step Hyp Ref Expression
1 ssequn1 ⊢ ( 𝐴 ⊆ 𝐵 ↔ ( 𝐴 ∪ 𝐵 ) = 𝐵 )
2 eleq1a ⊢ ( 𝐵 ∈ ω → ( ( 𝐴 ∪ 𝐵 ) = 𝐵 → ( 𝐴 ∪ 𝐵 ) ∈ ω ) )
3 2 adantl ⊢ ( ( 𝐴 ∈ ω ∧ 𝐵 ∈ ω ) → ( ( 𝐴 ∪ 𝐵 ) = 𝐵 → ( 𝐴 ∪ 𝐵 ) ∈ ω ) )
4 1 3 biimtrid ⊢ ( ( 𝐴 ∈ ω ∧ 𝐵 ∈ ω ) → ( 𝐴 ⊆ 𝐵 → ( 𝐴 ∪ 𝐵 ) ∈ ω ) )
5 ssequn2 ⊢ ( 𝐵 ⊆ 𝐴 ↔ ( 𝐴 ∪ 𝐵 ) = 𝐴 )
6 eleq1a ⊢ ( 𝐴 ∈ ω → ( ( 𝐴 ∪ 𝐵 ) = 𝐴 → ( 𝐴 ∪ 𝐵 ) ∈ ω ) )
7 6 adantr ⊢ ( ( 𝐴 ∈ ω ∧ 𝐵 ∈ ω ) → ( ( 𝐴 ∪ 𝐵 ) = 𝐴 → ( 𝐴 ∪ 𝐵 ) ∈ ω ) )
8 5 7 biimtrid ⊢ ( ( 𝐴 ∈ ω ∧ 𝐵 ∈ ω ) → ( 𝐵 ⊆ 𝐴 → ( 𝐴 ∪ 𝐵 ) ∈ ω ) )
9 nnord ⊢ ( 𝐴 ∈ ω → Ord 𝐴 )
10 nnord ⊢ ( 𝐵 ∈ ω → Ord 𝐵 )
11 ordtri2or2 ⊢ ( ( Ord 𝐴 ∧ Ord 𝐵 ) → ( 𝐴 ⊆ 𝐵 ∨ 𝐵 ⊆ 𝐴 ) )
12 9 10 11 syl2an ⊢ ( ( 𝐴 ∈ ω ∧ 𝐵 ∈ ω ) → ( 𝐴 ⊆ 𝐵 ∨ 𝐵 ⊆ 𝐴 ) )
13 4 8 12 mpjaod ⊢ ( ( 𝐴 ∈ ω ∧ 𝐵 ∈ ω ) → ( 𝐴 ∪ 𝐵 ) ∈ ω )