Metamath Proof Explorer


Theorem ordtoplem

Description: Membership of the class of successor ordinals. (Contributed by Chen-Pang He, 1-Nov-2015)

Ref Expression
Hypothesis ordtoplem.1 ⊢ ( ∪ 𝐴 ∈ On → suc ∪ 𝐴 ∈ 𝑆 )
Assertion ordtoplem ( Ord 𝐴 → ( 𝐴 ≠ ∪ 𝐴 → 𝐴 ∈ 𝑆 ) )

Proof

Step Hyp Ref Expression
1 ordtoplem.1 ⊢ ( ∪ 𝐴 ∈ On → suc ∪ 𝐴 ∈ 𝑆 )
2 df-ne ⊢ ( 𝐴 ≠ ∪ 𝐴 ↔ ¬ 𝐴 = ∪ 𝐴 )
3 ordeleqon ⊢ ( Ord 𝐴 ↔ ( 𝐴 ∈ On ∨ 𝐴 = On ) )
4 unon ⊢ ∪ On = On
5 4 eqcomi ⊢ On = ∪ On
6 id ⊢ ( 𝐴 = On → 𝐴 = On )
7 unieq ⊢ ( 𝐴 = On → ∪ 𝐴 = ∪ On )
8 5 6 7 3eqtr4a ⊢ ( 𝐴 = On → 𝐴 = ∪ 𝐴 )
9 8 orim2i ⊢ ( ( 𝐴 ∈ On ∨ 𝐴 = On ) → ( 𝐴 ∈ On ∨ 𝐴 = ∪ 𝐴 ) )
10 3 9 sylbi ⊢ ( Ord 𝐴 → ( 𝐴 ∈ On ∨ 𝐴 = ∪ 𝐴 ) )
11 10 orcomd ⊢ ( Ord 𝐴 → ( 𝐴 = ∪ 𝐴 ∨ 𝐴 ∈ On ) )
12 11 ord ⊢ ( Ord 𝐴 → ( ¬ 𝐴 = ∪ 𝐴 → 𝐴 ∈ On ) )
13 orduniorsuc ⊢ ( Ord 𝐴 → ( 𝐴 = ∪ 𝐴 ∨ 𝐴 = suc ∪ 𝐴 ) )
14 13 ord ⊢ ( Ord 𝐴 → ( ¬ 𝐴 = ∪ 𝐴 → 𝐴 = suc ∪ 𝐴 ) )
15 onuni ⊢ ( 𝐴 ∈ On → ∪ 𝐴 ∈ On )
16 eleq1a ⊢ ( suc ∪ 𝐴 ∈ 𝑆 → ( 𝐴 = suc ∪ 𝐴 → 𝐴 ∈ 𝑆 ) )
17 15 1 16 3syl ⊢ ( 𝐴 ∈ On → ( 𝐴 = suc ∪ 𝐴 → 𝐴 ∈ 𝑆 ) )
18 12 14 17 syl6c ⊢ ( Ord 𝐴 → ( ¬ 𝐴 = ∪ 𝐴 → 𝐴 ∈ 𝑆 ) )
19 2 18 biimtrid ⊢ ( Ord 𝐴 → ( 𝐴 ≠ ∪ 𝐴 → 𝐴 ∈ 𝑆 ) )