Metamath Proof Explorer


Theorem pconncn

Description: The property of being a path-connected topological space. (Contributed by Mario Carneiro, 11-Feb-2015)

Ref Expression
Hypothesis ispconn.1 ⊢ 𝑋 = ∪ 𝐽
Assertion pconncn ( ( 𝐽 ∈ PConn ∧ 𝐴 ∈ 𝑋 ∧ 𝐵 ∈ 𝑋 ) → ∃ 𝑓 ∈ ( II Cn 𝐽 ) ( ( 𝑓 ‘ 0 ) = 𝐴 ∧ ( 𝑓 ‘ 1 ) = 𝐵 ) )

Proof

Step Hyp Ref Expression
1 ispconn.1 ⊢ 𝑋 = ∪ 𝐽
2 1 ispconn ⊢ ( 𝐽 ∈ PConn ↔ ( 𝐽 ∈ Top ∧ ∀ 𝑥 ∈ 𝑋 ∀ 𝑦 ∈ 𝑋 ∃ 𝑓 ∈ ( II Cn 𝐽 ) ( ( 𝑓 ‘ 0 ) = 𝑥 ∧ ( 𝑓 ‘ 1 ) = 𝑦 ) ) )
3 2 simprbi ⊢ ( 𝐽 ∈ PConn → ∀ 𝑥 ∈ 𝑋 ∀ 𝑦 ∈ 𝑋 ∃ 𝑓 ∈ ( II Cn 𝐽 ) ( ( 𝑓 ‘ 0 ) = 𝑥 ∧ ( 𝑓 ‘ 1 ) = 𝑦 ) )
4 eqeq2 ⊢ ( 𝑥 = 𝐴 → ( ( 𝑓 ‘ 0 ) = 𝑥 ↔ ( 𝑓 ‘ 0 ) = 𝐴 ) )
5 4 anbi1d ⊢ ( 𝑥 = 𝐴 → ( ( ( 𝑓 ‘ 0 ) = 𝑥 ∧ ( 𝑓 ‘ 1 ) = 𝑦 ) ↔ ( ( 𝑓 ‘ 0 ) = 𝐴 ∧ ( 𝑓 ‘ 1 ) = 𝑦 ) ) )
6 5 rexbidv ⊢ ( 𝑥 = 𝐴 → ( ∃ 𝑓 ∈ ( II Cn 𝐽 ) ( ( 𝑓 ‘ 0 ) = 𝑥 ∧ ( 𝑓 ‘ 1 ) = 𝑦 ) ↔ ∃ 𝑓 ∈ ( II Cn 𝐽 ) ( ( 𝑓 ‘ 0 ) = 𝐴 ∧ ( 𝑓 ‘ 1 ) = 𝑦 ) ) )
7 eqeq2 ⊢ ( 𝑦 = 𝐵 → ( ( 𝑓 ‘ 1 ) = 𝑦 ↔ ( 𝑓 ‘ 1 ) = 𝐵 ) )
8 7 anbi2d ⊢ ( 𝑦 = 𝐵 → ( ( ( 𝑓 ‘ 0 ) = 𝐴 ∧ ( 𝑓 ‘ 1 ) = 𝑦 ) ↔ ( ( 𝑓 ‘ 0 ) = 𝐴 ∧ ( 𝑓 ‘ 1 ) = 𝐵 ) ) )
9 8 rexbidv ⊢ ( 𝑦 = 𝐵 → ( ∃ 𝑓 ∈ ( II Cn 𝐽 ) ( ( 𝑓 ‘ 0 ) = 𝐴 ∧ ( 𝑓 ‘ 1 ) = 𝑦 ) ↔ ∃ 𝑓 ∈ ( II Cn 𝐽 ) ( ( 𝑓 ‘ 0 ) = 𝐴 ∧ ( 𝑓 ‘ 1 ) = 𝐵 ) ) )
10 6 9 rspc2v ⊢ ( ( 𝐴 ∈ 𝑋 ∧ 𝐵 ∈ 𝑋 ) → ( ∀ 𝑥 ∈ 𝑋 ∀ 𝑦 ∈ 𝑋 ∃ 𝑓 ∈ ( II Cn 𝐽 ) ( ( 𝑓 ‘ 0 ) = 𝑥 ∧ ( 𝑓 ‘ 1 ) = 𝑦 ) → ∃ 𝑓 ∈ ( II Cn 𝐽 ) ( ( 𝑓 ‘ 0 ) = 𝐴 ∧ ( 𝑓 ‘ 1 ) = 𝐵 ) ) )
11 3 10 syl5com ⊢ ( 𝐽 ∈ PConn → ( ( 𝐴 ∈ 𝑋 ∧ 𝐵 ∈ 𝑋 ) → ∃ 𝑓 ∈ ( II Cn 𝐽 ) ( ( 𝑓 ‘ 0 ) = 𝐴 ∧ ( 𝑓 ‘ 1 ) = 𝐵 ) ) )
12 11 3impib ⊢ ( ( 𝐽 ∈ PConn ∧ 𝐴 ∈ 𝑋 ∧ 𝐵 ∈ 𝑋 ) → ∃ 𝑓 ∈ ( II Cn 𝐽 ) ( ( 𝑓 ‘ 0 ) = 𝐴 ∧ ( 𝑓 ‘ 1 ) = 𝐵 ) )